To find minimum and maximum number of students can go on trip.
Answer to Problem 5.4.1.5P
Minimum 67 students can go on trip
Maximum 133 students can go on trip
If bus having capacity of 100 students then maximum 100 student can go on trip.
Explanation of Solution
Given information:
Rent of bus is $1000
Cost of ticket to aquarium is $15
Total expense for trip must be $2000 to $3000
Calculation:
Letx number of students go on trip
Total cost for aquarium=15x
The Inequality are,
Subtracting 1000 all sides of compound inequality,
On solving,
Dividing by 15 both sides,
On solving,
Approximate,
Minimum 67 students can go on trip
Maximum 133 students can go on trip
If bus having capacity of 100 students then maximum 100 student can go on trip.
Chapter ISG Solutions
Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
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