Chapter EP, Problem 13.4.5EP

To determine

To find:The value of each triangle round to the nearest tenth.

Answer to Problem 13.4.5EP

The angle is $C=95°$ and other two sides are $a=6.2,b=6.9$ .

Explanation of Solution

Given information:The dimensions of triangle are $A=60,C=25,c=3$

Calculation:

The sum of the angles in a triangle is $180°$ .

$\begin{array}{c}A+B+C=180°\\ 60°+B+25°=180°\\ B=95°\end{array}$

Use the law of since $\frac{\sin A}{a}=\frac{\sin B}{b}$ To get,

  $\begin{array}{c}b=\frac{\sin B}{\sin C}\times c\\ =\frac{\sin 95}{\sin 25}\times 3\\ =6.9\end{array}$

Use the law of since $\frac{\sin A}{a}=\frac{\sin C}{c}$ to get,

  $\begin{array}{c}a=\frac{\sin A}{\sin C}\times c\\ =\frac{\sin 60}{\sin 25}\times 3\\ =6.2\end{array}$

Therefore, third angle is $C=95°$ and other two sides are $a=6.2,b=6.9$ .