Chapter E, Problem 11.11EX

To determine

To find the area of the segment AB of a circle with radius 6.

Answer to Problem 11.11EX

Option (c)

Explanation of Solution

Given information: Sector of the circle with radius 6 units and sector angle at ${90}^{°}$

Concept used:

  $\text{Area of the segment}=\frac{\theta }{{360}^{°}}\times \pi r^2-\frac{\sin \theta }{2}\times r^2$

Here, $\theta ={90}^{°};r=6$

  $\text{Area of the segment}=\frac{90}{{360}^{°}}\times 36\pi -\frac{1}{2}\times 36=9\pi -18$

Hence, the area of the segment AB is $9\pi -18$ units .