Chapter A.8, Problem 56AYU

To determine

To find: Length and width of the rectangle?

Answer to Problem 56AYU

$L=6$ and $w=3$

Explanation of Solution

Given:

If the piece of sheet metal is a rectangle whose length is twice its width.

Calculation:

$L=2w$

$\left(2w-2\right)\left(w-2\right)=4$

$\left(w-1\right)\left(w-2\right)=2$

$w^2-3w+2=2$

That is $w\left(w-3\right)=0$.

$w=3$

$L=6$