Explanation Given information: The equation of plane is 3 x − 2 y + z = − 1 a and point is P ( a , 2 a , 3 a ) & a ≠ 0 Formula Used: Distance of a point P ( x ∘ , y ∘ , z ∘ ) from a plane a x + b y + c z + D = 0 is given by d = | A x 0 + B y 0 + Cz 0 +D | A 2 + B 2 + C 2 Calculation: It is given that equation of plane is 3 x − 2 y + z = − 1 a o r 3 x − 2 y + z + 1 a = 0 On comparing with A x + B y + Cz+D = 0 A = 3 , B = − 2 , C = 1 & D = 1 a The point is P ( a , 2 a , 3 a ) = ( x 0 , y 0 , z 0

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 9.6, Problem 21PS

To determine

To find: Distance of a point P(a,2a,3a) from a plane 3x−2y+z=−1a .

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Chapter 9.6, Problem 20PS

Chapter 9.6, Problem 22PS

Chapter 9 Solutions

Calculus

Ch. 9.1 - Prob. 1PS Ch. 9.1 - Prob. 2PS Ch. 9.1 - Prob. 3PS Ch. 9.1 - Prob. 4PS Ch. 9.1 - Prob. 5PS Ch. 9.1 - Prob. 6PS Ch. 9.1 - Prob. 7PS Ch. 9.1 - Prob. 8PS Ch. 9.1 - Prob. 9PS Ch. 9.1 - Prob. 10PS

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Distance of a point P ( a , 2 a , 3 a ) from a plane 3 x − 2 y + z = − 1 a .

Solution Summary: The author explains the formula used to find the distance of a point from the plane.

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To find: Distance of a point P(a,2a,3a) from a plane 3x−2y+z=−1a .

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Chapter 9 Solutions