Explanation Given: ( x 2 + y 2 ) i + y j = 20 i + ( x + 2 ) j Concept Used: If two vectors v = 〈 x 1 , y 1 〉 and w = 〈 x 2 , y 2 〉 are equal, then x 1 = y 1 , x 2 = y 2 . Calculation: To find all real x and y that satisfies the equation ( x 2 + y 2 ) i + y j = 20 i + ( x + 2 ) j Compare the coefficients of left hand and right vector, as ( x 2 + y 2 ) i + y j = 20 i + ( x + 2 ) j ⇒ x 2 + y 2 = 20 and y = x + 2 Now, solve the above equation to get value of x and y, as x 2 + ( x + 2 ) 2 = 20 putting y = x + 2 x 2

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 9.1, Problem 27PS

To determine

To find all real x and y that satisfies the equation

(x2+y2)i+yj=20i+(x+2)j .

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Chapter 9.1, Problem 26PS

Chapter 9.1, Problem 28PS

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Chapter 9 Solutions

Calculus

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To find all real x and y that satisfies the equation ( x 2 + y 2 ) i + y j = 20 i + ( x + 2 ) j .

Solution Summary: The author explains how to find all real x and y that satisfies the equation.

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To find all real x and y that satisfies the equation

(x2+y2)i+yj=20i+(x+2)j .

Want to see the full answer?

Chapter 9 Solutions

To find all real x and y that satisfies the equation ( x 2 + y 2 ) i + y j = 20 i + ( x + 2 ) j .

Solution Summary: The author explains how to find all real x and y that satisfies the equation.

Concept explainers

Videos

To find all real x and y that satisfies the equation (x2+y2)i+yj=20i+(x+2)j .

Want to see the full answer?

Chapter 9 Solutions

To find all real x and y that satisfies the equation

(x2+y2)i+yj=20i+(x+2)j .