In Exercises 5–16, test the given claim.
8. Second-Hand Smoke Data Set 12 “Passive and Active Smoke” includes cotinine levels measured in a group of smokers (n = 40,
a. Use a 0.05 significance level to test the claim that the variation of cotinine in smokers is greater than the variation of cotinine in nonsmokers not exposed to tobacco smoke.
b. The 40 cotinine measurements from the nonsmoking group consist of these values (all in ng/mL): 1, 1, 90, 244, 309, and 35 other values that are all 0. Does this sample appear to be from a
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Chapter 9 Solutions
Elementary Statistics (13th Edition)
- Lecture(10.5): Use the following table to a answer the following question SS df MS F statistic Between/Treatments 246 3 Within/Error 20 Total 1215 (a) What is the calculated value for SSwithin? (b)What is the calculated value for MSbetween? (c) What is the calculated value for MSwithin?.arrow_forwardA sociologist wants to determine if the life expectancy of people in Africa is less than the life expectancy of people in Asia. The data obtained is shown in the table below. Africa Asia = 63.3 yr. 1 X,=65.2 yr. 2 o, = 9.1 yr. = 7.3 yr. n1 = 120 = 150arrow_forwardThe following table summarizes the percentage frequency of admitted students in SQU (2018) Defect code Percentage Frequency Bachelor 0.733 Master 0.206 Postgraduate Diploma 0.044 PhDarrow_forward
- A prospective cohort study is run to estimate the incidence of stroke in persons 55 years of age and older. All participants are free of stroke at study start. Each participant is followed for a maximum of 5 years. The data are summarized in Table 3–14. Number of Strokes Number of Stroke-Free Person-Years Men (n = 125) 9 478 Women (n = 200) 21 97 What is the annual incidence rate of stroke in men? What is the annual incidence rate of stroke in women? What is the annual incidence rate of stroke (men and women combined)?arrow_forwardThe data found below measure the amounts of greenhouse gas emissions from three types of vehicles. The measurements are in tons per year, expressed as CO2 equivalents. Use a 0.05 significance level to test the claim that the different types of vehicle have the same mean amount of greenhouse gas emissions. Based on the results, does the type of vehicle appear to affect the amount of greenhouse gas emissions?arrow_forward12:31 AM AME • 4_57830...4250162 8 Assignment One 1. Classify each of the following variables as quantitative or qualitative and state their measurement scale. (a) Age (in years) (b) Age in categories (0–20, 21–35, 36–45, 45–60, 60–85, 85+) (d) Toxicity (mild, moderate, life-threatening, dead) (e) Blood pressure (f) Time of flight of a missile 2. Consider the following score of 56 students out of 40 as data sets. 31 33 33 34 34 35 35 17 31 36 17 18 19 25 26 27 27 19 20 22 31 36 38 13 22 22 35 36 28 28 29 30 30 36 11 13 16 17 17 22 22 23 23 23 23 24 24 24 25 27 27 28 28 30 13 16 Use these data to prepare: (a) a frequency distribution, a relative frequency distribution and a cumulative frequency distribution. (b) a Histogram, frequency polygon and Ogive curve (c) Mean, Median and Mode. (d) Range, Mean deviation about mean, Mean deviation about median, Variance, Standard deviation and coefficient of variation and interpret the results. 3. A. The following is the frequency distribution of…arrow_forward
- A paper gives data on x = change in Body Mass Index (BMI, in kilograms/meter?) and y = change in a measure of depression for patients suffering from depression who participated in a pulmonary rehabilitation program. The table below contains a subset of the data given in the paper and are approximate values read from a scatterplot in the paper. BMI Change (kg/m²) 0.5 -0.5 0.1 0.7 0.8 1 1.5 1.2 1 0.4 0.4 Depression Score Change -1 4 4 5 8 13 14 17 18 12 14 The accompanying computer output is from Minitab. Fitted Line Plot Depression score change = 6.512 + 5.472 BMI change 5.26270 20- R-Sq R-Sq (adj) 19.88% 27.16% 15- 10- 5- 0- -0.5 0.0 0.5 1.0 1.5 BMI change R-są 5.26270 27.16% Coefficients Term Coef SE Coef T-Value P-Value VIF 6.512 5.472 Constant 2.26 2.88 0.0164 BMI change 2.83 1.93 0.0823 1.00 Regression Equation Depression score change = 6.512 + 5.472 BMI change (a) What percentage of observed variation in depression score change can be explained by the simple linear regression…arrow_forwardWhat percentage of women that did not receive the treatment showed hair growth of 1-2 inches? Answer: Blank 1: Blank 2: Blank 3: Blank 4: Chp -> & #3 $4 9. 8 6. 3 4. y earrow_forward5.3 2.4 3.5 5.2 (Reference: Crime in the United States, Federal Bureau of Investigation.) Assume that the crime rate distribution is approximately normal in both regions. i, Use a calculator to verify that x 3.51, s, = 0.81, x, = 3.87, and 0.94. i/ Do the data indicate that the violent crime rate in the Rocky Mountain region is higher than that in New England? Use a = 0.01. %3D Medical: Hay Fever A random sample of n, = 16 communities in western Kansas gave the following information for people under 25 years of age. x,: Rate of hay fever per 1000 population for people under 25 120 128 92 123 112 93 86 06 125 95 125 122 88 L6 Arandom sample of n, = 14 regions in western Kansas gave the following information for people over 50 years old. x,: Rate of hay fever per 1000 population for people over 50 95 110 97 112 88 85 110 115 114 68 96 (Reference: National Center for Health Statistics.) i. Use a calculator to verify that x 109.50, s, - 15.41, x2 - 99.36, and sh 11.57. ii. Assume that the…arrow_forward
- Calcium is essential to tree growth because it promotes the formation of wood and maintains cell walls. In 1990, the concentration of calcium in precipitation in a certain area was 0.12 milligrams per liter (mg/L). A random sample of 10 precipitation dates in 2007 results in the following data table. Complete parts (a) through (c) below. Click the icon to view the data table. - Data table (a) State the hypotheses for determining if the mean concentration of calcium precipitation has changed since 1990. Ho: P = 0.12 mg/L H₁: μ # 0.12 mg/L 0.074 0.075 0.071 0.257 0.116 0.177 0.107 0.247 0.333 0.102 (b) Construct a 90% confidence interval about the sample mean concentration of calcium precipitation. The lower bound is The upper bound is Print (Round to four decimal places as needed.) Done Xarrow_forwardA paper gives data on x = change in Body Mass Index (BMI, in kilograms/meter) and y = change in a measure of depression for patients suffering from depression who participated in a pulmonary rehabilitation program. The table below contains a subset of the data given in the paper and are approximate values read from a scatterplot in the paper. BMI Change (kg/m2) 0.7 0.8 1 1.5 1.2 1 0.4 0.4 0.5 -0.5 0.1 Depression Score Change -1 | 4 5 8 13 14| 17| 18| 12 14 The accompanying computer output is from Minitab. Fitted Line Plot Depression score change = 6.512 + 5.472 BMI change 5.26270 20 - R-Sq R-Sq (adj) 19.88% 27.16% 15- 10-. 5- -0.5 0.0 0.5 1.0 1.5 BMI change 5.26270 27.166 Coefficients Term Coef SE Coef T-Value P-Value VIF Constant 6.512 2.26 2.88 0.0164 BMI change 5.472 2.83 1.93 0.0823 1.00 Regression Equation Depression score change = 6.512 + 5.472 EMI change (a) What percentage of observed variation in depression score change can be explained by the simple linear regression model?…arrow_forward20) The residual is the difference between the and the A) predicted value of y; observed value of y B) observed value of y; predicted value of y C) predicted value of x; observed value of x D) observed value of x; predicted value of yarrow_forward
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