Algebra 2
Algebra 2
1st Edition
ISBN: 9780078884825
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Question
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Chapter 9.3, Problem 29PPS

a.

To determine

To write an equation representing the speed as a function of time.

a.

Expert Solution
Check Mark

Answer to Problem 29PPS

The required function is r=60.5t .

Explanation of Solution

Given information:

The given statement is:

“The distance from the pitcher’s mound to home plate is 60.5 feet .”

The speed of the pitch is r and the time it takes the ball to get to the plate is t .

The equation representing the speed as a function of time.

  r=60.5t    [Speed=distancetime] .

Hence, the required function is r=60.5t .

b.

To determine

To graph the function.

b.

Expert Solution
Check Mark

Explanation of Solution

Given information:

The given function is:

  r=60.5t

Graph:

This represents a transformation of the graph of f(x)=1x .

  a=60.5 : The graph is expanded.

  h=0 : There is an asymptote at t=0 .

  k=0 : There is an asymptote at r=0 .

The graph of the function is:

  Algebra 2, Chapter 9.3, Problem 29PPS

Interpretation:

The domain of the graph is all real numbers not equal to 0 and the range is all real numbers except 0 .

c.

To determine

To find the speed.

c.

Expert Solution
Check Mark

Answer to Problem 29PPS

The speed of the two-seam fastball is 126 feet/sec .

Explanation of Solution

Given information:

The given statement is:

“If a two-seam fastball reaches the plate in 0.48 second , what was its speed?”

The function is r=60.5t .

Calculation:

The speed can be calculated by:

  r=60.5tr=60.50.48  [Substitute the value of t]r≈126 feet/sec

Hence, the speed of the two-seam fastball is 126 feet/sec .

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Chapter 9.3, Problem 28PPS
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Chapter 9.3, Problem 30PPS

Chapter 9 Solutions

Algebra 2

Ch. 9.1 - Prob. 1ACYPCh. 9.1 - Prob. 1BCYPCh. 9.1 - Prob. 2CYPCh. 9.1 - Prob. 3ACYPCh. 9.1 - Prob. 3BCYPCh. 9.1 - Prob. 4ACYPCh. 9.1 - Prob. 4BCYPCh. 9.1 - Prob. 4CCYPCh. 9.1 - Prob. 4DCYPCh. 9.1 - Prob. 5ACYP
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