Concept explainers
a.
To discover: prove something interesting about point
a.
Answer to Problem 19WE
Point
Explanation of Solution
Given:
Two tangents
For the larger circle, EG and GH are two tangents drawn from a common point G.
By the property of tangents, if two tangents of the circle are drawn from a common point, then their length are equal.
Thus,
Now, for the smaller circle, GH and FG are two tangents drawn from a common point G.
By the property of tangents, if two tangents of the circle are drawn from a common point, then their length are equal.
Thus,
Concluding from equation (i) and (ii),
Hence, G is the midpoint of the common external tangent EF of both the circle.
Conclusion:
Therefore,
b.
To discover: prove something interesting about
b.
Answer to Problem 19WE
Explanation of Solution
Given:
Two tangent circles;
Since
A circle can be constructed with G as the center and
In the circle with center G, EF is the diameter and
By the property of circle, any angle made in a semicircular arc is always a right angle, it can be easily said that
Therefore,
Conclusion:
Therefore,
Chapter 9 Solutions
McDougal Littell Jurgensen Geometry: Student Edition Geometry
Additional Math Textbook Solutions
Introductory Statistics
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (4th Edition)
College Algebra (6th Edition)
Mathematics for Elementary Teachers with Activities (5th Edition)
College Algebra
Introductory and Intermediate Algebra for College Students (5th Edition)
- Elementary Geometry For College Students, 7eGeometryISBN:9781337614085Author:Alexander, Daniel C.; Koeberlein, Geralyn M.Publisher:Cengage,Elementary Geometry for College StudentsGeometryISBN:9781285195698Author:Daniel C. Alexander, Geralyn M. KoeberleinPublisher:Cengage Learning