Explanation The p - v diagram of the Diesel cycle is shown below. Figure-(1) Write the expression for compression ratio. r = v 1 v 1 − v s (I) Here, the volume at point 1 is v 1 and the displacement volume is v s . Write the expression between, temperature and compression ratio for process 1-2. T 2 T 1 = ( r ) k − 1 (II) Here, the adiabatic index is k , the temperature at compressor outlet is T 2 , the compressor inlet is T 1 and the compression ratio is r . Write the expression for the cutoff ratio. r c = T 3 T 2 (III) Here, the temperature at point 3 is T 3 and at point 2 is T 2 , the volume of cylinder before expansion is V 3 and after compression is V 2 . Write the expression between, temperature and cutoff ratio for process 4-1. T 4 T 1 = ( r c ) k (IV) Here, the temperature at point 4 is T 4 and at point 1 is T 1 and the cutoff ratio is r c . Write the expression for the inlet volume at point 1. v 1 = m R T 1 p 1 (V) Here, the gas constant is R and mass of the air is m . Write the expression the net developed. w n e t = m [ c p ( T 3 − T 2 ) − c v ( T 4 − T 1 ) ] (VI) Here, the mass of the air is m , engine rpm is N . Write the expression for the net power of the cycle. W ˙ n e t = w n e t × N (VII) Write the expression for the thermal efficiency of diesel cycle. % η t h = w n e t m c p ( T 3 − T 2 ) . N × 100 % (VIII) Conclusion: Substitute 3.17 L for v 1 and 3 L for v s in Equation (I). r = 3.17 L 3.17 L − 3 L = 3.17 L 0.17 L = 19 Substitute 19 for r , 1.4 for k and 295 K for T 1 in Equation (II). T 2 295 K = ( 19 ) 1.4 − 1 T 2 = 295 K × ( 19 ) 0.4 T 2 = 958 K Substitute 958 K for T 2 and 2.5 for r c in Equation (II). 2.5 = T 3 958 K T 3 = 2395 K Substitute 2.5 for r c , 1.4 for k and 295 K for T 1 in Equation (III). T 4 295 K = ( 2.5 ) 1.4 T 4 = 295 K × ( 2.5 ) 1.4 T 4 = 1064 K Substitute 295 K for T 1 , 95 kPa for p 1 , 0.00317 m 3 for v 1 and 0.287 kJ / kg ⋅ K in Equation (IV)

Fundamentals of Engineering Thermodynamics

8th Edition

ISBN: 9781118412930

Author: Michael J. Moran, Howard N. Shapiro, Daisie D. Boettner, Margaret B. Bailey

Publisher: WILEY

See similar textbooks

Question

Chapter 9.14, Problem 28P

To determine

The net work developed.

The thermal efficiency.

The net power for the cycle.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 9.14, Problem 27P

Chapter 9.14, Problem 29P

Students have asked these similar questions

5. Determine the transfer function of G(s) = 01(s)/T₁(s) and 02(s)/T₁ for the mechanical system shown in Figure Q5. (Hints: assume zero initial condition) T₁(t) 01(t) 102(1) Ол N1 D1 D2 No. 1790220000 N2 Figure Q5 K2

A spring package with two springs and an external force, 200N. The short spring has a loin of 35 mm. Constantly looking for spring for short spring so that total compression is 35 mm (d). Known values: Long spring: Short spring:C=3.98 N/mm Lo=65mmLo=87.4mmF=c·fTotal compression is same for both spring. 200 = (3.98(c1) × 35) + (c₂ × 35) 200 = 139.3 + 35c₂ 200 - 139.3 = 35c₂ 60.7 = 35c₂ c₂ = 60.7/35 Short spring (c₂) = 1.73 N/mm According to my study book, the correct answer is 4.82N/mm What is wrong with the calculating?

What is the reason for this composition?

Chapter 9 Solutions

Fundamentals of Engineering Thermodynamics

Ch. 9.14 - Prob. 1E Ch. 9.14 - Prob. 2E Ch. 9.14 - Prob. 3E Ch. 9.14 - Prob. 4E Ch. 9.14 - Prob. 5E Ch. 9.14 - 6. What is the purpose of a rear diffuser on a...Ch. 9.14 - 7. What is the meaning of the octane rating that...Ch. 9.14 - Prob. 8E Ch. 9.14 - Prob. 9E Ch. 9.14 - 10. What is the purpose of the gas turbine–powered...

Knowledge Booster

The net work developed. The thermal efficiency. The net power for the cycle.

The net work developed. The thermal efficiency. The net power for the cycle.

Want to see the full answer?

Chapter 9 Solutions

The net work developed.

The thermal efficiency.

The net power for the cycle.