(a) Explanation Write the expression for the pressure at exit state. p 2 = ( p r 2 p r 1 ) p 1 (I) Here, the pressure at state 2 is p 2 , the reduced pressure at state 1 is p r 1 , the reduced pressure at state 2 is p r 2 and the pressure at state 1 is p 1 . Write the expression for the specific enthalpy in terms of compressor efficiency at exit state. h 2 = h 1 + ( V 1 2 − V 2 2 2 ) (II) Here, the specific enthalpy at state 1 is h 1 , the specific enthalpy at state 2 is h 2 the specific volume at state 1 is V 1 and the specific volume at state 2 is V 2 . Conclusion: Refer to table A-22E “ideal gas properties of air” to obtain the specific enthalpy and reduced pressure at temperature T 1 = 800 ° R as 191.81 Btu / lb and 5.526 . Substitute 191.81 Btu / lb for h 1 , 480 ft / s for V 1 and 1500 ft / s for V 2 in Equation (I). h 2 = 191.81 Btu / lb + ( ( 480 ft / s ) 2 − ( 1500 ft / s ) 2 2 ) = 191.81 Btu / lb − 1009800 ft 2 / s 2 ( 1 lbf ⋅ s 2 32 (b) To determine The ratio of the exit area to inlet area. (c) To determine The type of the nozzle.

Fundamentals of Engineering Thermodynamics

8th Edition

ISBN: 9781118412930

Author: Michael J. Moran, Howard N. Shapiro, Daisie D. Boettner, Margaret B. Bailey

Publisher: WILEY

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Chapter 9.14, Problem 129P

(a)

To determine

The exit pressure.

(b)

To determine

The ratio of the exit area to inlet area.

(c)

To determine

The type of the nozzle.

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Chapter 9.14, Problem 127P

Chapter 9.14, Problem 130P

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