a) Explanation Draw the P − v diagram for an Otto cycle as shown in Figure (1). Write the expression of thermal efficiency of the given Otto cycle ( η th ) . η th = 1 − 1 r k − 1 (I) Here, the compression ratio of air is r , and the specific heat ratio of air is k . Conclusion: From Table A-2a, “Ideal-gas specific heats of various common gases”, obtain the following values of air at room temperature. c p = 1.005 kJ / kg ⋅ K c v = 0 b) To determine The thermal efficiency of the Otto cycle with variable specific heats.

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Author: CENGEL

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Chapter 9.12, Problem 160RP

To determine

The thermal efficiency of the given Otto cycle with constant specific heat.

To determine

The thermal efficiency of the Otto cycle with variable specific heats.

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Chapter 9.12, Problem 159RP

Chapter 9.12, Problem 161RP

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A spring package with two springs and an external force, 200N. The short spring has a loin of 35 mm. Constantly looking for spring for short spring so that total compression is 35 mm (d). Known values: Long spring: Short spring:C=3.98 N/mm Lo=65mmLo=87.4mmF=c·fTotal compression is same for both spring. 200 = (3.98(c1) × 35) + (c₂ × 35) 200 = 139.3 + 35c₂ 200 - 139.3 = 35c₂ 60.7 = 35c₂ c₂ = 60.7/35 Short spring (c₂) = 1.73 N/mm According to my study book, the correct answer is 4.82N/mm What is wrong with the calculating?

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The thermal efficiency of the given Otto cycle with constant specific heat.

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The thermal efficiency of the given Otto cycle with constant specific heat.

The thermal efficiency of the Otto cycle with variable specific heats.

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