Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
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Chapter 9, Problem 9.7.4P
To determine
The adequate strength of the composite section by LFRD method.
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A composite floor system consists of steel beams supporting a formed steel deck and concrete slab. The deck is shown in Figure P, and the total depth from bottom of deck to top of slab is 61⁄2 inches. Lightweight concrete is used (unit weight =115 pcf), and the 28-day compressive strength is 4 ksi. The deck and slab combination weighs 53 psf. The beams are spaced at 12 feet, and the span length is 40 feet. There is a 20psf construction load, a partition load of 20 psf, other dead load of 10 psf, and a live load of 160 psf. The maximum permissible live-load deflection is Ly/360. Use the composite beam tables and select a W-shape with Fy= 50 ksi. Design the stud anchors. Use partial composite action and a lowerbound moment of inertia. a. Use LRFD. b. Use ASD
Homework3 A simply supported concrete slab given the section depth is 100mm, concrete grade is C30 and reinforcement grade is HPB300. The span of slab is 19=2.38m. The live load applied on the slab is ge=2kN/m2 and the dead load include: 1. Its self-weight given concrete (include reinforcement) bulk density is 28kN/m3 2. Terrazzo floor and fine stone cushion layer is 30mm(bulk density is 22kN/m) and the ceiling plaster mortar is 12mm(bulk density 17kN/m²).
4. An interior reinforced concrete slab has to be designed to support a live load and a
dead load in addition to its own weight based on the following specifications:
The slab is one-way and simply supported with a span of 12 ft.
The live load on the slab is 200 psf.
The dead load on the slab is 100 psf.
Your design will use concrete compressive strength fe= 3000 psi and steel
yield strength of fy = 40,000 psi
Chapter 9 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 9 - Prob. 9.1.1PCh. 9 - Prob. 9.1.2PCh. 9 - Prob. 9.1.3PCh. 9 - Prob. 9.1.4PCh. 9 - Prob. 9.1.5PCh. 9 - Prob. 9.1.6PCh. 9 - A W1422 acts compositely with a 4-inch-thick floor...Ch. 9 - Prob. 9.2.2PCh. 9 - Prob. 9.3.1PCh. 9 - Prob. 9.3.2P
Ch. 9 - Prob. 9.4.1PCh. 9 - Prob. 9.4.2PCh. 9 - Prob. 9.4.3PCh. 9 - Prob. 9.4.4PCh. 9 - Prob. 9.4.5PCh. 9 - Prob. 9.5.1PCh. 9 - Prob. 9.5.2PCh. 9 - Prob. 9.5.3PCh. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Prob. 9.7.1PCh. 9 - Prob. 9.7.2PCh. 9 - Prob. 9.7.3PCh. 9 - Prob. 9.7.4PCh. 9 - Prob. 9.8.1PCh. 9 - Prob. 9.8.2PCh. 9 - A beam must be designed to the following...Ch. 9 - Prob. 9.8.4PCh. 9 - Prob. 9.8.5PCh. 9 - Prob. 9.8.6PCh. 9 - Prob. 9.8.7PCh. 9 - Prob. 9.8.8PCh. 9 - Use the composite beam tables and select a W-shape...Ch. 9 - Prob. 9.8.10PCh. 9 - Prob. 9.10.1PCh. 9 - Prob. 9.10.2P
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