Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 9, Problem 9.6.5P
Note For Problems 9.6-1 through 9.6-5, use the lower-bound moment of inertia for deflection of the composite section. Compute this as illustrated in Example 9.7.
9.6-5 For the beam of Problem 9.4-2.
a. Compute the deflections that occur before and after the concrete has cured.
b. It the live toad deflection exceeds
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A beam cast monolithically has the following properties: bf=1200mm, t or hf = 110mm, bw=380mm and h=800mm. It is reinforced with 10D32mm grade 420MPa bars. Concrete strength is assumed to be 27.5MPa and the centroid of tension reinforcement is located 665mm from the outermost compression fiber.
A. Determine maximum nominal moment to ensure tension controlled, kN-m.
B. Calculate the balanced steel area, mm2.
C. Calculate the balanced moment in kN-m.
Details of a rectangular column are as follows:
Column width along X-axis-250 mm
Column Depth along the Y-axis-600 mm
8-25 mm diameter bars distributed equally along the longer sides.
10 mm diameter ties spaced at 10 mm on centers
Concrete 28th day Compressive strength, fc;=20.7 MPa
Reinforcing Steel yield strength, fy-415 MPa
Assume that compression steel yields.
a) Which of the following gives the nominal balanced load Pb (kN). A = 90.4 mm
b) Which of the following gives the nominal axial load (kN) that the column n carry at an
eccentricity of 200 mm along the X axis from the centroidal Y-axis.
The rectangular doubly reinforcement stress concrete block with the arrangement of reinforcement of 2N28
bars on top and 3N28 bars on bottom. The modulus of elasticity are Ec =23,500MPa and Es = 200,000MPa.
Dead load is 18KN/m and live load is 12KN/m.
f' = 25MPa
800
IDE
730
N12 ligs (fsv.f-500MPa)
Ast = 3N28
350
Span = 10m
Figure 3
Calculate the combination load for the reinforcement concrete beam shown in Figure 3. Unit: KN/m
with two decimal. 1.2G+1.5Q=w
Chapter 9 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 9 - Prob. 9.1.1PCh. 9 - Prob. 9.1.2PCh. 9 - Prob. 9.1.3PCh. 9 - Prob. 9.1.4PCh. 9 - Prob. 9.1.5PCh. 9 - Prob. 9.1.6PCh. 9 - A W1422 acts compositely with a 4-inch-thick floor...Ch. 9 - Prob. 9.2.2PCh. 9 - Prob. 9.3.1PCh. 9 - Prob. 9.3.2P
Ch. 9 - Prob. 9.4.1PCh. 9 - Prob. 9.4.2PCh. 9 - Prob. 9.4.3PCh. 9 - Prob. 9.4.4PCh. 9 - Prob. 9.4.5PCh. 9 - Prob. 9.5.1PCh. 9 - Prob. 9.5.2PCh. 9 - Prob. 9.5.3PCh. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Note For Problems 9.6-1 through 9.6-5, use the...Ch. 9 - Prob. 9.7.1PCh. 9 - Prob. 9.7.2PCh. 9 - Prob. 9.7.3PCh. 9 - Prob. 9.7.4PCh. 9 - Prob. 9.8.1PCh. 9 - Prob. 9.8.2PCh. 9 - A beam must be designed to the following...Ch. 9 - Prob. 9.8.4PCh. 9 - Prob. 9.8.5PCh. 9 - Prob. 9.8.6PCh. 9 - Prob. 9.8.7PCh. 9 - Prob. 9.8.8PCh. 9 - Use the composite beam tables and select a W-shape...Ch. 9 - Prob. 9.8.10PCh. 9 - Prob. 9.10.1PCh. 9 - Prob. 9.10.2P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
- Compute for the beam shown. Use psi and psi. Does the compression steel yield in this beam at nominal strength?arrow_forwardASAP DONT REJECT ME, I'LL GIVE UPVOTE THANK YOUU Solve the basic development lengths in tension for the following deformed bars embedded in normal-weight concrete. State if you have assumptions. (a) 12mm bar dia; 32 mm bar dia. fy = 41.4 MPa fy = 413.7 MPa (b) 44mm bar dia; 57 mm bar dia. f c = 28 MPa fy = 552 MPaarrow_forwardSub: Advance Reinforced Concrete design. Follow the ACI 318 design code for the design. Answer the question with all details. provide the drawings with all details. Don't Copy Paste from Other Solutions please. i will Upvote You Value Óf X1= 27.65 Value Of X2= 395 1- Design the beam BC of the frame shown in Figure 1 for bending moment and shear force according to ACI 318 code requirements. The concrete cover is 30 mm. Dead load and live loads are given in Figure 1. Provide all drawings in detail. Please do check for maximum and minimum flexural requirements, maximum and minimum spacing of the shear reinforcement. f=X1 MPa, fy=X2 MPa D.L.=5 ton/m L.L.= 3 ton/m 6 m 3 marrow_forward
- Using the stress block, determine the ultimate moment of resistance of the section shown in Figure 2 and check whether the steei provided satisfies the bending moment due to the loads on the beam. Characteristic compressive strength of concrete, fck= 25 N/mm² Characteristic tensile strength of steel, fyk = 500 N/mm2 Clear cover to main steel as 20 mm. Ultimate Design Load =13 kN/m 2 402 mm 370 mm 2 1470 mm 9 m 230 mm Figure 2arrow_forwardA beam has a width of 300 mm and an effective depth of 480 mm strength Pc= 34 MPa. Steel yield strength fy=415 MPa. The section is to be reinforced for tension only and the effective concrete cover is 70 mm. Deadload moment is 140 kN-m and the liveload moment is 180 kN-m. Use 2010 NSCP with t= 0.005. A. What is the governing steel ratio? B. What is the maximum number of bars needed for a 25mm diameter reinforcements? C. What is the minimum number of bars needed for a 25mm diameter reinforcements?arrow_forwardA W18 x 40 floor beam supports a 4-inch-thick reinforced concrete slab with an effective width b of 81 inches. Sufficient anchors are provided to make the beam fully composite. The 28-day compressive strength of the concrete is f,c = 4 ksi. a. Compute the moment of inertia of the transformed section. b. For a positive service load moment of 290 ft-kips, compute the stress at the top of the steel (indicate whether tension or compression), the stress at the bottom of the steel, and the stress at the top of the concrete.arrow_forward
- A rectangular beam has the dimensions (see Figure) b = 12 in, h= 20 in, and d= 17 in. and is reinforced with three No. 9 (No. 29) bars so that As - 3.00 in?. The concrete compressive strength fe is 4000 psi, and the tensile strength in bending (modulus of rupture) is 475 psi. The yield point of the steel f, is 60,000 psi. Determine the stress in the steel caused by a bending moment M = 10 ft-kips. 9 - 6.78 in, I- 4067 in, Es = 29000000, E - 3600000 L17 in. 20 in. 3 #9 bars (A, - 3.00 in.) 3 in. -12 in.- Select one: a. 2525 psi b. 2412 psi C. 2615 psi d. 2817 psiarrow_forwardA short post is made by filling a standard6x6x steel tube with conerete, as shown in Figure P3-67. The steel has an allowable stress of 21 600 psi. The concrete has a rated strength of 6000 psi. but, in this application, the stress is to be limited to 1500 psi. See Section 2-10 for the modulus of elasticity for the concrete. Compute the allowable load on the post.arrow_forwardUSE NSCP 2010 A simply supported beam is reinforced with 4 – 28 mm ø at the bottomand 2 – 28 mm ø at the top of the beam. Steel covering to centroid ofreinforcement is 70 mm at the top and bottom of the beam. The beamhas a total depth of 400 mm and a widthof 300 mm. fc’ = 30 MPa, fy = 415 MPa. Balanced steel ratio ρb = 0.031.Compute the ultimate moment capacity of the beam in kN-m. Usereduction factor of 0.90arrow_forward
- Fill in the blanks: Determine the required tension steel area of the T beam with given properties below. Width of flange bf= 500 mm Width of web bw = 400mm Thickness of flange tf 140 mm Effective depth d = 380 mm Effective concrete covering d' = 75 mm Compressive strength of concrete fc' = 30 MPa Yield stress of steel bar fy = 300 MPa Mu = 448 kN-m As = mm2 CS Scanned with CamScannerarrow_forward*4-36. The composite bar consists of a 20-mm-diameter A-36 steel segment AB and 50-mm-diameter red brass C83400 end segments DA and CB. Determine the average normal stress in each segment due to the applied load. Esteel l = 200 x10 Pa. EBrass = 101 K109h. |-250 mm-- 500 mm -250 mm- 50 mm 20 mm 75 kN 100 kN D A 75 kN 100 kN В Carrow_forwardUse the composite beam tables and select a W-shape and stud anchors for the following conditions: Span length = 18 6 Beam spacing = 9 ft Total slab thickness = 51 2 in. (the slab and deck combination weighs 57 psf). Lightweight concrete with a unit weight of 115 pcf is used Construction load = 20 psf Partition load = 20 psf Live load = 225 psf Fy=50 ksi and fc=4 ksi A cross section of the formed steel deck is shown in Figure P9.8-9. The maximum live-load deflection cannot exceed L/360 (use a lower-bound moment of inertia). a. Use LRFD. b. User ASD.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Steel Design (Activate Learning with these NEW ti...Civil EngineeringISBN:9781337094740Author:Segui, William T.Publisher:Cengage LearningMaterials Science And Engineering PropertiesCivil EngineeringISBN:9781111988609Author:Charles GilmorePublisher:Cengage Learning
Steel Design (Activate Learning with these NEW ti...
Civil Engineering
ISBN:9781337094740
Author:Segui, William T.
Publisher:Cengage Learning
Materials Science And Engineering Properties
Civil Engineering
ISBN:9781111988609
Author:Charles Gilmore
Publisher:Cengage Learning
The History of Composite Materials, From Brick to Bakelite to Biomimetic Hybrids; Author: Autodesk;https://www.youtube.com/watch?v=VS_Kg-VEvzE;License: Standard YouTube License, CC-BY