Chapter 9, Problem 9.69QP

(a)

Interpretation Introduction

Interpretation:

The volumes of given solutions are should be determined.

Concept introduction:

Mole:

The mole of compound is given by the ratio between taken mass of the compound and molecular mass of compound.

$\text{Mole}\text{=}\frac{\text{Mass}\text{(g)}}{\text{Molecular}\text{mass}\text{(g)}}$

Volume:

The Volume of solution is given by the ratio between mole of the solute and molarity of the solution.

$\text{Volume}\text{=}\frac{\text{Mole}}{\text{Molarity}}$

(b)

Interpretation Introduction

Interpretation:

The volumes of given solutions are should be determined.

Concept introduction:

Mole:

The mole of compound is given by the ratio between taken mass of the compound and molecular mass of compound.

$\text{Mole}\text{=}\frac{\text{Mass}\text{(g)}}{\text{Molecular}\text{mass}\text{(g)}}$

Volume:

The Volume of solution is given by the ratio between mole of the solute and molarity of the solution.

$\text{Volume}\text{=}\frac{\text{Mole}}{\text{Molarity}}$

(c)

Interpretation Introduction

Interpretation:

The volumes of given solutions are should be determined.

Concept introduction:

Mole:

The mole of compound is given by the ratio between taken mass of the compound and molecular mass of compound.

$\text{Mole}\text{=}\frac{\text{Mass}\text{(g)}}{\text{Molecular}\text{mass}\text{(g)}}$

Volume:

The Volume of solution is given by the ratio between mole of the solute and molarity of the solution.

$\text{Volume}\text{=}\frac{\text{Mole}}{\text{Molarity}}$