The robot moves the particle A (mass M) in the vertical plane using polar coordinate formulas r(t) = 1,2-0,6sin(2πt) [m] θ(t) = 0,5-1,5cos(2πt) [rad] in accordance with. Determine the acceleration of the body in the r-direction [m / s2] at time t0 = 1.9 s Use units [m/s2] GIVE ANSWER TO THREE DECIMALS

A basketball star covers 2.80 m horizontally in a jump to dunk the ball . His motion through space can be modeled precisely as that of a particle at his center of mass, which we will define in Chapter 9. His center of mass is at elevation 1.02 m when he leaves the floor. It reaches a maximum height of 1.85 m above the floor and is at elevation 0.900 m when he touches down again. Determine (a) his time of flight (his “hang time”), (b) his horizontal and (c) vertical velocity components at the instant of takeoff, and (d) his takeoff angle. (e) For comparison, determine the hang time of a whitetail deer making a jump with center-of-mass elevations yi =1.20 m, ymax =2.50 m, and yf =0.700 m.

A basketball star covers 2.85 m horizontally in a jump to dunk the ball. His motion through space can be modeled precisely as that of a particle at his center of mass. His center of mass is at elevation 1.02 when he leaves the floor. It reaches a maximum height of 1.75 m above the floor and is at elevation 0.860 m when he touches down again. (a) Determine his time of flight (his "hang time"). .81 S (b) Determine his horizontal velocity at the instant of takeoff. 3.52 m/s (c) Determine his vertical velocity at the instant of takeoff. 4.167 X Your response differs from the correct answer by more than 10%. Double check your calculations. m/s (d) Determine his takeoff angle. ° above the horizontal (e) For comparison, determine the hang time of a whitetail deer making a jump with center-of-mass elevations y; = 1.20 m, max = 2.55 m, and y₁ = 0.700 m. Need Help? Read It