A water molecule consists of an oxygen atom with two hydrogen atoms bound to it.  The angle between the two bonds is 106°. If bonds are 0.100 nm long, where is the center of mass of the molecule?

The 200-g projectile is fired with a velocity of  900 m >s towards the center of the 15-kg wooden blockwhich rests on a rough surface. If the projectile penetrates  and emerges from the block with a velocity of 300 m >s,  determine the velocity of the block just after the projectile  emerges. How long does the block slide on the rough  surface, after the projectile emerges, before it comes to rest  again? The coefficient of kinetic friction between the  surface and the block is mk = 0.2

GO In Fig. 9-45a, a 4.5 kg dog stands on an 18 kg flatboat at dis- 0•17 Dog's displacement da tance D = 6.1 m from the shore. It walks 2.4 m along the boat toward shore and then stops. Assuming no friction between the boat and the wa- Boat's displacement d, ter, find how far the dog is then from the shore. (Hint: See Fig. 9-45b.) (b) Figure 9-45 Problem 17.

Radical Albertan separatists are driving a tank at a constant speed of 10 m/s up a 45 degree mountain slope, in a vain attempt to invade British Columbia. Pursued by the Mounties, the tank fires a 10 kg watermelon, with muzzle velocity 25 m/s, back along its path. Ignore the distance from the muzzle to the slope. If the gun barrel is pointed 20 degrees above the horizontal as shown, how far is the melon from the tank (which keeps moving) when it finally strikes the slope below? Answer in m.

52. The Center of Mass of Sulfur Dioxide Sulfur dioxide (SO₂) consists of two oxygen atoms (each of mass 16 u, where u is defined in Problem 40) and a single sulfur atom (of mass 32 u). The center-to-center distance between the sulfur atom and either of the oxygen atoms is 0.143 nm, and the angle formed by the three atoms is 120°, as shown in Figure 9-20. Find the x and y coordinates of the center of mass of this molecule. Oxygen 0.143 nm y 120° Oxygen 0.143 nm Sulfur A FIGURE 9-20 Problem 52 I

A metal soda can of uniform composition has a mass of 0.134 kg and is 12.6 cm tall (see the figure). The can is filled with 1.42 kg of soda. Then small holes are drilled in the top and bottom (with negligible loss of metal) to drain the soda. What is the height h of the center of mass of the can and contents (a) initially and (b) after the can loses all the soda? (c) If x is the height of the remaining soda at any given instant, find x when the center of mass reaches its lowest point. (a) Number i Units (b) Number i Units (c) Number i Units Splash!

Consider the schematic of the molecule shown, with two hydrogen atoms, H, bonded to an oxygen atom, O. The angle between the two bonds is 106°. If the bond length r = 0.099 nm long, locate the center of mass of the molecule. The mass m of the hydrogen atom is 1.008 u, and the mass mo of the oxygen atom is 15.9999 u. (Use a coordinate system centered in the oxygen atom, with the x-axis to the right and the y-axis upward. Give the coordinates of the center of mass in nm.) XCM Усм = = 0 H усм 53⁰ I = nm 53° Use trigonometry to determine the y-coordinate of the hydrogen molecules. Then apply the definition Σmyi Σmi nm r H

Consider the schematic of the molecule shown, with two hydrogen atoms, H, bonded to an oxygen atom, O. The angle between the two bonds is 106°. If the bond length r= 0.110 nm long, locate the center of mass of the molecule. The mass m, of the hydrogen atom is 1.008 u, and the mass mo of the oxygen atom is 15.9999 u. (Use a coordinate system centered in the oxygen atom, with the x-axis to the right and the y-axis upward. Give the coordinates of the center of mass in nm.) 53 nm YCH nm Submt Answer

A water molecule consists of an oxygen atom with two hydrogen atoms bound to it (see the figure below). Suppose the angle between the two bonds is 104°. If the bonds are 0.0850 nm long, where is the center of mass of the molecule? (Take the origin to be the center of the oxygen atom and the x axis to be along the dotted line.) x = 0.00563 x Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. nm y = 0v nm 53 53 H. H