EBK ENGINEERING FUNDAMENTALS: AN INTROD
EBK ENGINEERING FUNDAMENTALS: AN INTROD
5th Edition
ISBN: 9780100543409
Author: MOAVENI
Publisher: YUZU
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Chapter 9, Problem 49P
To determine

Calculate the quantity of available water to unit -4.

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Answer to Problem 49P

The quantity of available water to unit 4 in gallonsmin, ft3s, m3s, lbms, and kgs are 54.7gallonsmin_, 0.122ft3s,0.00345m3s,7.6lbms,and3.45kgs respectively.

Explanation of Solution

Calculation:

Consider that the density of the water is generally known as 62.4lbmft3.

density=62.4lbmft3

Convert the unit from lbmft3 to lbmgallon.

density=62.4lbmft3(1ft37.48052gallons)[1ft3=7.48052gallons]=8.34lbmgallon

Consider that the unit-1 water consumption rate.

Unit-1 consumption rate=18lbms

Convert the unit from lbms to gallonsmin.

Unit-1 consumption rate=18lbms(60s1min)(1gallons8.34lbm)     [1min=60s,and1gallons=8.34lbm]=129.5gallonsmin

Consider that the unit-2 water consumption rate.

Unit-2 consumption rate=18lbms

Convert the unit from lbms to gallonsmin.

Unit-2 consumption rate=14lbms(60s1min)(1gallons8.34lbm)         [1min=60s,and1gallons=8.34lbm]=100.7gallonsmin

Consider that the unit-3 water consumption rate.

Unit-3 consumption rate=18lbms

Convert the unit from lbms to gallonsmin.

Unit-3 consumption rate=16lbms(60s1min)(1gallons8.34lbm)        [1min=60s,and1gallons=8.34lbm]=115.1gallonsmin

The amount of water available to unit-4 is,

The amount of water available to unit-4={wateravailablerateunit-1 consumption rateunit-2 consumption rateunit-3 consumption rate}

Substitute 400gallonsmin for water available rate, 129.5gallonsmin for unit-1 consumption rate, 100.7gallonsmin for unit-2 consumption rate, and 115.1gallonsmin for unit-3 consumption rate.

The amount of water available to unit-4={[400gallonsmin129.5gallonsmin100.7gallonsmin115.1gallonsmin]}

The amount of water available to unit-4=54.7gallonsmin (1)

Convert the unit of equation (1) from gallonsmin to ft3s.

density=54.7gallonsmin(1ft37.48052gallons)(1min60s)   [1ft3=7.48052gallons,and1min=60s]=0.122ft3s

Convert the unit from ft3s to m3s.

density=0.122ft3s(0.3048m1ft)3[1ft=0.3048m]=0.00345m3s

Convert the unit of equation (1) from gallonsmin to lbms.

density=54.7gallonsmin(1lbms7.19gallonsmin)[1lbms=7.19gallonsmin]=7.6lbms

Convert the unit from lbms to kgs.

density=7.6×0.453592kgs[1lbm=0.453592kg]=3.45kgs

Conclusion:

Thus, the quantity of available water to unit 4 in gallonsmin, ft3s, m3s, lbms, and kgs are 54.7gallonsmin_, 0.122ft3s,0.00345m3s,7.6lbms,and3.45kgs respectively.

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