CAMPBEL BIOLOGY:CONCEPTS & CONNECTIONS
10th Edition
ISBN: 9780136538820
Author: Taylor
Publisher: INTER PEAR
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Chapter 9, Problem 3TYK
Edward was found to be heterozygous (Ss) for sickle-cell trait. The alleles represented by the letters S and s are
a. linked.
b. on homologous chromosomes.
c. both present in each of Edward’s sperm cells.
d. on the same chromosome but far apart.
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Students have asked these similar questions
Hemophilia is a disease caused by a gene found on the X
chromosome. Therefore, it is referred to as a sex-linked disease.
The recessive allele causes the disease. A man with hemophilia
(xhy) marries a woman who is homozygous dominant (XHXH.
A. Illustrate using a Punnett square the probability that their children
will have the disease.
B. Will any of their children have the disease?
C. Predict the probabilities of their children having the disease.
Edward was found to be heterozygous (Ss) for the sickle-cell trait. The alleles represented by the letters S and s are a. on the X and Y chromosomes. b. linked. c. on homologous chromosomes. d. both present in each of Edward’s sperm cells.
Hemophilia is a disease caused by a gene found on the X chromosome. Therefore, it is a sex-linked disease which is caused by the recessive allele. Suppose, a man with hemophilia marries a woman who is homozygous dominant for the trait, what is the chance of having children who are hemophiliacs? (XH = normal; Xh= hemophiliac) *
a. 0%
b. 75%
c. 100%
d. 25%
Chapter 9 Solutions
CAMPBEL BIOLOGY:CONCEPTS & CONNECTIONS
Ch. 9 - Connecting the Concepts 1. Complete this concept...Ch. 9 - Whether an allele is dominant or recessive depends...Ch. 9 - Edward was found to be heterozygous (Ss) for...Ch. 9 - Two fruit flies with eyes of the usual red color...Ch. 9 - A man with type B blood and a woman who has type A...Ch. 9 - Tim and Jan both have freckles (see Module 9.9),...Ch. 9 - Both Tim and Jan (problem 6) have a widows peak...Ch. 9 - In rabbits, black hair depends on a dominant...Ch. 9 - A fruit fly with a gray body and red eyes...Ch. 9 - A series of matings shows that the recombination...
Ch. 9 - A couple are both phenotypically normal, but their...Ch. 9 - Why do more men than women have colorblindness?Ch. 9 - In fruit flies, the genes for wing shape and body...Ch. 9 - Adult height in humans is at least partially...Ch. 9 - Heather was surprised to discover she suffered...Ch. 9 - In 1981, a stray black cat with unusual rounded,...Ch. 9 - SCIENTIFIC THINKING The breakthrough that led...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
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- A man who has color blindness and type O blood has children with a woman who has normal color vision and type AB blood. The woman’s father had color blindness. Color blindness is determined by an X-linked gene, and blood type is determined by an autosomal gene. a. What are the genotypes of the man and the woman? b. What proportion of their children will have color blindness and type B blood? c. What proportion of their children will have color blindness and type A blood? d. What proportion of their children will be color blind and have type AB blood?arrow_forwardTay–Sachs disease is caused by recessive alleles on anautosome. In which case(s) could two parents with anormal phenotype have a child with Tay–Sachs?a. Both parents are homozygous for a Tay–Sachs allele.b. Both parents are heterozygous for a Tay–Sachsallele.c. One parent is homozygous for a Tay–Sachs allele,and the other is heterozygous.arrow_forwardIn humans, hemophilia is an X-linked recessive condition characterized by the inability of blood to clot normally. A woman who is a carrier for hemophilia marries a man who has hemophilia. What are the genotypes of the woman and man, respectively? a. xH+xH+, xH+y b. xH+xH xH+y c. xH+xH xHy Od. XHXH, XH+y O e. xHxH xHyarrow_forward
- Assume that one of Merida's sons, who is heterozygous for orange hair color, married a girl that was also heterozygous. Create a Punnett square to show the possibilities that would result if they had children. a. List the possible genotypes and phenotypes for their children. b. What are the chances of a child with orange hair? c. What are the chantes of a child with yellow?arrow_forwardHemophilia is a disease caused by a recessive allele (h), which is found on the X chromosome, non-hemophilia is (H). A normal man marries a woman that is heterozygous for the trait. Give the genotypes and phenotypes of all possible offspring?arrow_forwardEarlobes can be attached to the face or non-attached. An attached earlobe is a recessive trait. A female with attached earlobes (Il) has a child with a man with non-attached earlobes. He is heterozygous for this trait. Questions: a. What are the possible genotypes of the egg the woman can produce? b. What are the possible genotypes of the sperm the man can produce? c. What is the genotype ratio for the offspring? d. What is the phenotype ratio for the offspring? e. What is the couple's chance of having a child with attached earlobes?arrow_forward
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