Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
10th Edition
ISBN: 9781337399074
Author: John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher: Cengage Learning
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Chapter 9, Problem 22PS

Platinum hexafluoride is an extremely strong oxidizing agent. It can even oxidize oxygen, its reaction with O2 giving O2+PtFt6. Sketch the molecular orbital energy level diagram for the O2+ ion. How many net σ and π bonds does the ion have? What is the oxygen-oxygen bond order? How has the bond order changed on taking away electrons from O2 to obtain O2+? Is the O2+ ion paramagnetic?

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Platinum hexafluoride is an extremely strong oxidizing agent. It can even oxidize oxygen, its reaction with O2 giving O2+PtF6−.a. Sketch the molecular orbital energy level diagram for the O2+ ion.b. How many net σ and π bonds does the ion have?c. What is the O-O bond order?d. How has the bond order changed on taking away electrons from O2 to obtain O2+?e. Is the O2+ ion paramagnetic?
Use the molecular orbital model to fully describe the bonding in O2+, O2, O2-, and O22-.Determine which of the following statements are true and which are false. True or false? : Bond length increases with increasing bond order while bond energy decreases.The number of unpaired electrons in O2- and O2 is, respectively, 1 and 2. The electron configuration of O2 is (σ2s)2(σ2s*)2(σ2p)2(π2p)4(π2p*)1.  The electron configuration of O2- is (σ2s)2(σ2s*)2(σ2p)2(π2p)4(π2p*)3.  The bond order in O2- and O22- is, respectively, 2.5 and 1.    The bond lengths increase in the order: O22- < O2- < O2 < O2+.
Write the best Lewis dot structure for NH₄⁺, being sure to give the electronic geometry, molecular geometry, hybridization of the central element, polarity, and bond angle around the central element.

Chapter 9 Solutions

Chemistry & Chemical Reactivity

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