To solve given equations.
Answer to Problem 22CT
The solutions are (-4, 6) (3, 13)
Explanation of Solution
Given information:
Here we shall substitute the value of
Hence we get,
Now we shall determine the values of
Now we shall put the values of
We get
Therefore the solutions are (-4, 6) (3, 13)
Chapter 9 Solutions
High School Math 2015 Common Core Algebra 1 Student Edition Grade 8/9
Additional Math Textbook Solutions
Elementary Algebra
Linear Algebra and Its Applications (5th Edition)
Intermediate Algebra (7th Edition)
College Algebra with Modeling & Visualization (6th Edition)
Introductory and Intermediate Algebra for College Students (5th Edition)
College Algebra (7th Edition)
- Algebra and Trigonometry (6th Edition)AlgebraISBN:9780134463216Author:Robert F. BlitzerPublisher:PEARSONContemporary Abstract AlgebraAlgebraISBN:9781305657960Author:Joseph GallianPublisher:Cengage LearningLinear Algebra: A Modern IntroductionAlgebraISBN:9781285463247Author:David PoolePublisher:Cengage Learning
- Algebra And Trigonometry (11th Edition)AlgebraISBN:9780135163078Author:Michael SullivanPublisher:PEARSONIntroduction to Linear Algebra, Fifth EditionAlgebraISBN:9780980232776Author:Gilbert StrangPublisher:Wellesley-Cambridge PressCollege Algebra (Collegiate Math)AlgebraISBN:9780077836344Author:Julie Miller, Donna GerkenPublisher:McGraw-Hill Education