Statistics for the Behavioral Sciences
Statistics for the Behavioral Sciences
3rd Edition
ISBN: 9781506386256
Author: Gregory J. Privitera
Publisher: SAGE Publications, Inc
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Chapter 9, Problem 20CAP

1.

To determine

Find the test statistic value and make a decision to retain or reject the null hypothesis

1.

Expert Solution
Check Mark

Answer to Problem 20CAP

The test statistic value is 3.

The decision is to reject the null hypothesis.

Explanation of Solution

Calculation:

Let μ1 is average rating of humorous comedians, and μ2 is average rating of non humorous comedians

A sample of 10 participants observed one of two comedians is considered and they are rated 7-point scale from 1 (not likable at all) to 7 (very likable). The claim is the there is difference between the likability ratings of two groups. This represents the alternative hypothesis. The level of significance is 0.05.

Null hypothesis:

H0:μ1=μ2

That is, there is no difference between the likability ratings of two groups.

Alternative hypothesis:

H1:μ1μ2

That is, there is difference between the likability ratings of two groups.

The degrees of freedom for t distribution is,

df=(n11)+(n21)=(51)+(51)=4+4=8

The test is two tailed, the degrees of freedom are 8, and the alpha level is 0.05.

From the Appendix C: Table C.2 the t Distribution:

  • Locate the value 8 in the degrees of freedom (df) column.
  • Locate the 0.05 in the proportion in Two tails combined row.
  • The intersecting value that corresponds to the 8 with level of significance 0.05 is 2.306.

Decision rules:

  • If the test statistic value is greater than the critical value, then reject the null hypothesis or else retain the null hypothesis.
  • If the negative test statistic value is less than negative critical value, then reject the null hypothesis or else retain the null hypothesis.

The formula of test statistic for one-sample t test is,

tobt=(M1M2)(μ1μ2)sM1M2

In the formula, M1 is first sample mean, M2 is second sample mean, μ1 is first population mean, μ2 is second population mean, sM2M2 is estimated standard error of difference given as,

sM2M2=sp2n1+sp2n2 and sp2=s12(df1)+s22(df2)df1+df2.

In the formula, s12 is the first sample standard deviation, s22 is the second sample standard deviation, df1 are the degrees of freedom for first sample and df2 are the degrees of freedom for second sample.

Software procedure:

Step by step procedure to obtain test statistic value using SPSS software is given as,

  • Choose Variable view.
  • Under the name, enter the names as Ratings, and Comedians.
  • Choose Data view, enter the data.
  • Choose Analyze>Compare means>Independent Samples T Test.
  • In Test variables, enter the column as Ratings.
  • In Grouping variables, enter the column as Comedians.
  • Select Define Groups; enter Group 1 as 1 and Group 2 as 2.
  • Click OK.

Output using SPSS software is given below:

Statistics for the Behavioral Sciences, Chapter 9, Problem 20CAP , additional homework tip  1

Statistics for the Behavioral Sciences, Chapter 9, Problem 20CAP , additional homework tip  2

Thus, the test statistic value is 3.

Justification: The value of test statistic is 3 and critical value is 2.306. The test statistic value is greater than the critical value. The test statistic value fall under critical region and hence the null hypothesis is rejected.

2.

To determine

Find the value of estimated Cohen’s d to compute the effect size.

2.

Expert Solution
Check Mark

Answer to Problem 20CAP

The value of estimated Cohen’s d is 1.90.

There is large effect size.

Explanation of Solution

Cohen’s d:

The Cohen’s d is the measure to estimate the effect size which is used most frequently for t test. In t test the value of population standard deviation is not known, hence this value is replaced with sample standard deviation for estimation the effect size as,

The Cohen’s d for a two-independent-sample t test is,

Cohen'sd=M1M2sp2

The description of effect size using Cohen’s d:

  • If value of Cohen’s d is less than 0.2, then effect size is small.
  • If value of Cohen’s d is in between 0.2 and 0.8, then effect size is medium.
  • If value of Cohen’s d is greater than 0.8, then effect size is large.

Calculation:

From the SPSS output, the value of (M1M2) is 3 and sp is 1.581. The value of Cohen’s d is,

d=M1M2sp2=31.581=1.90

The value of estimated Cohen’s d is 1.90. This value is greater than 0.8. Hence the estimated Cohen’s d has a large effect size.

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