Chapter 9, Problem 13STP

Use the partial chemical equation below to answer Question 12 and 13.

${\text{AlCl}}_{\text{3}}{\text{(aq) + Fe}}_{\text{2}}{\text{O}}_{\text{3}}\text{(aq)}\to$

13. Predict what the products of this reaction will be. Use evidence from the reaction to support your answer.

Interpretation Introduction

Interpretation:

The product of the reaction needs to be determined.

${\text{AlCl}}_{\text{3}}\left(\text{aq}\right){\text{+Fe}}_{\text{2}}{\text{O}}_{\text{3}}\left(\text{aq}\right)\to$

Concept introduction:

Replacement reactions are mainly classified into two types single and double-replacement reaction. In a single replacement reaction, the atom of one element displaces the atom of another element in a compound. Double-replacement reaction includes the transfer of ions between two compounds.

Answer to Problem 13STP

The product of the reaction is ${\text{Al}}_{\text{2}}{\text{O}}_3$ (aluminium oxide) and ${\text{FeCl}}_{\text{3}}$ iron (III) chloride.

Explanation of Solution

Double-replacement reactions are those in which an exchange of ions between two compounds takes place. The given equation is as follows:

${\text{AlCl}}_{\text{3}}\left(\text{aq}\right){\text{+Fe}}_{\text{2}}{\text{O}}_{\text{3}}\left(\text{aq}\right)\to$

In aqueous state reactant molecule dissociates to ions. The complete reaction is as follows:

${\text{AlCl}}_{\text{3}}\left(\text{aq}\right){\text{+Fe}}_{\text{2}}{\text{O}}_{\text{3}}\left(\text{aq}\right)\to {\text{Al}}_{\text{2}}{\text{O}}_3\left(\text{s}\right){\text{+2FeCl}}_{\text{3}}\left(\text{aq}\right)$

In this reaction anion ${\text{Cl}}^{-}$ and ${\text{O}}^{\text{2}}{}^{-}$ change places and bonded with ${\text{Al}}^{\text{3+}}$ and ${\text{Fe}}^{\text{3+}}$ cations.

Conclusion

In double-replacement reaction two compounds are take part in the reaction and produce two different compounds one of the product is a solid, gas or water.