INTRODUCTORY CHEMISTRY
8th Edition
ISBN: 2818000163285
Author: CORWIN
Publisher: PEARSON CO
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 9, Problem 10CE
Interpretation Introduction
Interpretation:
The total number complete bicycles that can be made by
Concept introduction:
The problem solving technique that is used to solve such problems in which the value of the single unit is find out first. Then this single unit value is multiplied by the significant value to get the accurate answer is known as unitary method.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A mixture of barium chloride and sulfuric acid yield the precipitate barium sulfate and hydrochloric acid according to the double replacement reaction:
A large quantity of barium chloride is used to ensure that the sulfuric acid is the limiting reactant. If 45.0 grams of barium sulfate are produced, what mass of H2SO4 must be dissolved in the initial aqueous solution?
_ g
[Number in standard notation; round your answer to one decimal place]
The following molar masses may or may not be needed, but are provided to save you time:
barium sulfate = 233 g/mol
sulfuric acid = 98.0 g/mol
Consider the reaction.
heat
2 Al(s) + Fe,O,(s)
→ Al, O, (s) + 2 Fe(1)
If 23.1 kg Al reacts with an excess of Fe, O,, how many kilograms of Al, O, will be produced?
mass of Al, 0, produced:
kg
Consider the reaction.
heat
2 Al(s) + Fe,0,(s)
Al,03(s) + 2 Fe(1)
If 11.5 kg Al reacts with an excess of Fe,O2, how many kilograms of Al,0, will be produced?
mass of Al,0, produced:
kg
Chapter 9 Solutions
INTRODUCTORY CHEMISTRY
Ch. 9 - Prob. 1CECh. 9 - Prob. 2CECh. 9 - Prob. 3CECh. 9 - Prob. 4CECh. 9 - Prob. 5CECh. 9 - Prob. 6CECh. 9 - Prob. 7CECh. 9 - Prob. 8CECh. 9 - Prob. 9CECh. 9 - Prob. 10CE
Ch. 9 - Prob. 11CECh. 9 - Prob. 12CECh. 9 - Prob. 13CECh. 9 - Prob. 1KTCh. 9 - Prob. 2KTCh. 9 - Prob. 3KTCh. 9 - Prob. 4KTCh. 9 - Prob. 5KTCh. 9 - Prob. 6KTCh. 9 - Prob. 7KTCh. 9 - Prob. 8KTCh. 9 - Prob. 9KTCh. 9 - Prob. 10KTCh. 9 - Prob. 11KTCh. 9 - Prob. 12KTCh. 9 - Prob. 13KTCh. 9 - Prob. 14KTCh. 9 - Prob. 15KTCh. 9 - Prob. 1ECh. 9 - Prob. 2ECh. 9 - Prob. 3ECh. 9 - Prob. 4ECh. 9 - Prob. 5ECh. 9 - Prob. 6ECh. 9 - Prob. 7ECh. 9 - Prob. 8ECh. 9 - Prob. 9ECh. 9 - Prob. 10ECh. 9 - Prob. 11ECh. 9 - Prob. 12ECh. 9 - Prob. 13ECh. 9 - Prob. 14ECh. 9 - Prob. 15ECh. 9 - Prob. 16ECh. 9 - Prob. 17ECh. 9 - Prob. 18ECh. 9 - Prob. 19ECh. 9 - Prob. 20ECh. 9 - Prob. 21ECh. 9 - Prob. 22ECh. 9 - Prob. 23ECh. 9 - Prob. 24ECh. 9 - Prob. 25ECh. 9 - Prob. 26ECh. 9 - Prob. 27ECh. 9 - Prob. 28ECh. 9 - Prob. 29ECh. 9 - Prob. 30ECh. 9 - Prob. 31ECh. 9 - Prob. 32ECh. 9 - Prob. 33ECh. 9 - Prob. 34ECh. 9 - Prob. 35ECh. 9 - Prob. 36ECh. 9 - Prob. 37ECh. 9 - Prob. 38ECh. 9 - Prob. 39ECh. 9 - Prob. 40ECh. 9 - Prob. 41ECh. 9 - Prob. 42ECh. 9 - Prob. 43ECh. 9 - Prob. 44ECh. 9 - Prob. 45ECh. 9 - Prob. 46ECh. 9 - Prob. 47ECh. 9 - Prob. 48ECh. 9 - Prob. 49ECh. 9 - Prob. 50ECh. 9 - Prob. 51ECh. 9 - Prob. 52ECh. 9 - Prob. 53ECh. 9 - Prob. 54ECh. 9 - Prob. 55ECh. 9 - Prob. 56ECh. 9 - Prob. 57ECh. 9 - Prob. 58ECh. 9 - Prob. 59ECh. 9 - Prob. 60ECh. 9 - Prob. 61ECh. 9 - Prob. 62ECh. 9 - Prob. 63ECh. 9 - Prob. 64ECh. 9 - Prob. 65ECh. 9 - Prob. 66ECh. 9 - Prob. 67ECh. 9 - Prob. 68ECh. 9 - Prob. 69ECh. 9 - Prob. 70ECh. 9 - Prob. 71ECh. 9 - Prob. 72ECh. 9 - Prob. 73ECh. 9 - Prob. 74ECh. 9 - Prob. 75ECh. 9 - Prob. 76ECh. 9 - Prob. 77ECh. 9 - Prob. 78ECh. 9 - Prob. 79ECh. 9 - Prob. 80ECh. 9 - Prob. 81ECh. 9 - Prob. 82ECh. 9 - Prob. 83ECh. 9 - Prob. 84ECh. 9 - Prob. 85ECh. 9 - Prob. 86ECh. 9 - Prob. 87ECh. 9 - Prob. 88ECh. 9 - Prob. 89ECh. 9 - Prob. 90ECh. 9 - Prob. 1STCh. 9 - Prob. 2STCh. 9 - Prob. 3STCh. 9 - Prob. 4STCh. 9 - Prob. 5STCh. 9 - Prob. 6STCh. 9 - Prob. 7STCh. 9 - Prob. 8STCh. 9 - Prob. 9STCh. 9 - Prob. 10STCh. 9 - Prob. 11STCh. 9 - Prob. 12STCh. 9 - Prob. 13STCh. 9 - Prob. 14STCh. 9 - Prob. 15ST
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- hat do the coefficients of a balanced chemical equation tell us about the proportions in which atoms and molecules react on an individual (microscopic) basis?arrow_forward4.36 Sometimes students in chemistry labs determine percentage yields greater than 100%. Assuming there is no calculation error, how could this happen?arrow_forwardlist at least three quantities that must be conserved in chemical reactions.arrow_forward
- What mass of solid NaOH (97.0% NaOH by mass) is required to prepare 1.00 L of a 10.0% solution of NaOH by mass? The density of the 10.0% solution is 1.109 g/mL.arrow_forward4.3 Explain the difference between complete and incomplete combustion.arrow_forwardWhen corn is allowed to ferment, the fructose in the corn is converted to ethyl alcohol according to the following reaction C6H12O6(aq)2C2H5OH(l)+2CO2(g)(a) What volume of ethyl alcohol (d=0.789g/mL) is produced from one pound of fructose? (b) Gasohol can be a mixture of 10 mL ethyl alcohol and 90 mL of gasoline. How many grams of fructose are required to produce the ethyl alcohol in one gallon of gasohol?arrow_forward
- a. Write die balanced equation for the combustion of isooctane (C8H18) to produce water vapor and carbon dioxide gas. b. Assuming gasoline is 100.% isooctane, with a density of 0.692 g/mL, what is the theoretical yield of carbon dioxide produced by the combustion of 1.2 1010 gal of gasoline (the approximate annual consumption of gasoline in the United States)?arrow_forwardA power plant is driven by the combustion of a complex fossil fuel having the formula C11H7S. Assume the air supply is composed of only N2 and O2 with a molar ratio of 3.76:1.00, and the N2 remains unreacted. In addition to the water produced, the fuels C is completely combusted to CO2 and its sulfur content is converted to SO2. In order to evaluate gases emitted at the exhaust stacks for environmental regulation purposes, the nitrogen supplied with the air must also be included in the balanced reactions. a Including the N2 supplied m the air, write a balanced combustion equation for the complex fuel assuming 100% stoichiometric combustion (i.e., when there is no excess oxygen in the products and the only C-containing product is CO2). Except in the case of N2, use only integer coefficients. b Including N2 supplied in the air, write a balanced combustion equation for the complex fuel assuming 120% stoichiometric combustion (i.e., when excess oxygen is present in the products and the only C-containing product is CO2). Except in the case of use only integer coefficients c Calculate the minimum mass (in kg) of air required to completely combust 1700 kg of C11H7S. d Calculate the air/fuel mass ratio, assuming 100% stoichiometric combustion. e Calculate the air/fuel mass ratio, assuming 120% stoichiometric combustion.arrow_forward8.00 grams of sodium sulfate dissolves in water. This is then reacted with 8.00grams of calcium chloride dissolved in water. Sodium chloride and another compound are the products. How many grams of the second product are produced?arrow_forward
- A laboratory technician measures 1.60 g of CuCl2(s) and prepares a solution. Whenthe solution is complete, a 150-mg piece of Al(s) is placed into the solution and left to react. Calculate the mass of copper produced when the reaction is completearrow_forwardConsider a small bird of mass 30 g. What is the minimum mass of glucose that it must consume (and burn) to fly up to a branch 10 m above the ground?arrow_forwardFor the reaction 2 Mg(s) + O2(g) → 2MgO, a reaction mixture contains 33.7 g Mg and 28.0 g O2. The theoretical yield of MgO is _ g. Report your answer to three significant figures. Do not include units in your answer.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStax
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
Introductory Chemistry: A Foundation
Chemistry
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry by OpenStax (2015-05-04)
Chemistry
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:OpenStax
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
World of Chemistry, 3rd edition
Chemistry
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Brooks / Cole / Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Bonding (Ionic, Covalent & Metallic) - GCSE Chemistry; Author: Science Shorts;https://www.youtube.com/watch?v=p9MA6Od-zBA;License: Standard YouTube License, CC-BY
Stoichiometry - Chemistry for Massive Creatures: Crash Course Chemistry #6; Author: Crash Course;https://www.youtube.com/watch?v=UL1jmJaUkaQ;License: Standard YouTube License, CC-BY