Explanation The electron configuration of Ne having atomic number 10 is 1s 2 2 s 2 2 p 6 . Therefore, the total number of electrons present in Ne 2 molecule are 20 . Therefore, the electronic configuration of Ne 2 molecule is, ( σ 1s ) 2 ( σ 1 s ∗ ) 2 ( σ 2s ) 2 ( σ 2s ∗ ) 2 ( σ 2p z ) 2 ( π 2 p x ) 2 ( π 2 p y ) 2 ( π 2 p x ∗ ) 2 ( π 2 p y ∗ ) 2 ( σ 2p z ∗ ) 2 The bond order of Ne 2 is calculated by the formula, Bond order = 1 2 ( N b − N a ) Where, N b is the number of electrons present in bonding molecular orbital. N a is the number of electrons present in anti bonding molecular orbital. Substitute the value of 10 for N b and 10 for N a in the above formula as it has 10 electron in the bonding MO and 10 electrons in the antibonding molecular orbital. Bond order = 1 2 ( 10 − 10 ) = 0 Therefore, the bond order of Ne 2 molecule is 0 . The electron configuration of N having atomic number 7 is 1s 2 2 s 2 2 p 3 . Therefore, the total number of electrons present in N 2 + ion are 13 . Therefore, the electronic configuration of N 2 + molecule is, ( σ 1s ) 2 ( σ 1 s ∗ ) 2 ( σ 2s ) 2 ( σ 2s ∗ ) 2 ( π 2 p x ) 2 ( π 2 p y ) 2 ( σ 2p z ) 1 Therefore, the bond order of N 2 + ion is calculated by the formula, Bond order = 1 2 ( N b − N a ) Where, N b is the number of electrons present in bonding molecular orbital. N a is the number of electrons present in anti bonding molecular orbital. Substitute the value of 9 for N b and 4 for N a in the above formula as it has 9 electron in the bonding MO and 4 electrons in the antibonding molecular orbital. Bond order = 1 2 ( 9 − 4 ) = 5 2 = 2.5 Therefore, the bond order of N 2 + ion is 2.5 . The electron configuration of B having atomic number 5 is 1s 2 2 s 2 2 p 1 . Therefore, the total number of electrons present in B 2 molecule are 10 . Therefore, the electronic configuration of B 2 molecule is, ( σ 1s ) 2 ( σ 1 s ∗ ) 2 ( σ 2s ) 2 ( σ 2s ∗ ) 2 ( π 2 p x ) 1 ( π 2 p y ) 1 Therefore, the bond order of B 2 is calculated by the formula, Bond order = 1 2 ( N b − N a ) Where, N b is the number of electrons present in bonding molecular orbital

Chemistry: The Central Science (14th Edition)

14th Edition

ISBN: 9780134414232

Author: Theodore E. Brown, H. Eugene LeMay, Bruce E. Bursten, Catherine Murphy, Patrick Woodward, Matthew E. Stoltzfus

Publisher: PEARSON

See similar textbooks

Concept explainers

Formal Charges

Formal charges have an important role in organic chemistry since this concept helps us to know whether an atom in a molecule is neutral/bears a positive or negative charge. Even if some molecules are neutral, the atoms within that molecule need not be ne…

Polarity Of Water

In simple chemical terms, polarity refers to the separation of charges in a chemical species leading into formation of two polar ends which are positively charged end and negatively charged end. Polarity in any molecule occurs due to the differences in t…

Valence Bond Theory Vbt

Valence bond theory (VBT) in simple terms explains how individual atomic orbitals with an unpaired electron each, come close to each other and overlap to form a molecular orbital giving a covalent bond. It gives a quantum mechanical approach to the forma…

Videos

Question

Chapter 9, Problem 106AE

Interpretation Introduction

To determine: The arrangement of the given molecules and ions from smallest to the largest bond order.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 9, Problem 105AE

Chapter 9, Problem 107AE

Students have asked these similar questions

Indicate how to find the energy difference between two levels in cm-1, knowing that its value is 2.5x10-25 joules.

The gyromagnetic ratio (gamma) for 1H is 2.675x108 s-1 T-1. If the applied field is 1,409 T what will be the separation between nuclear energy levels?

Chances Ad ~stract one 11. (10pts total) Consider the radical chlorination of 1,3-diethylcyclohexane depicted below. 4 • 6H total $4th total Statistical pro 21 total 2 H A 2H 래 • 4H totul < 3°C-H werkest bund - abstraction he leads to then mo fac a) (6pts) How many unique mono-chlorinated products can be formed and what are the structures for the thermodynamically and statistically favored products? рос 6 -વા J Number of Unique Mono-Chlorinated Products Thermodynamically Favored Product Statistically Favored Product b) (4pts) Draw the arrow pushing mechanism for the FIRST propagation step (p-1) for the formation of the thermodynamically favored product. Only draw the p-1 step. You do not need to include lone pairs of electrons. No enthalpy calculation necessary H H-Cl

Chapter 9 Solutions

Chemistry: The Central Science (14th Edition)

Ch. 9.2 - Consider the following AB3 molecules and ions-...Ch. 9.2 - Prob. 9.1.2PE Ch. 9.2 - Prob. 9.2.1PE Ch. 9.2 - Prob. 9.2.2PE Ch. 9.2 - Prob. 9.3.1PE Ch. 9.2 - Prob. 9.3.2PE Ch. 9.3 - Prob. 9.4.1PE Ch. 9.3 - Determine whether the following molecules are...Ch. 9.5 - Prob. 9.5.1PE Ch. 9.5 - Prob. 9.5.2PE

Ch. 9.6 - Prob. 9.6.1PE Ch. 9.6 - Prob. 9.6.2PE Ch. 9.6 - Prob. 9.7.1PE Ch. 9.6 - Prob. 9.7.2PE Ch. 9.7 - Prob. 9.8.1PE Ch. 9.7 - Prob. 9.8.2PE Ch. 9.8 - Prob. 9.9.1PE Ch. 9.8 - Prob. 9.9.2PE Ch. 9 - Prob. 1DE Ch. 9 - 9.1 A certain AB4, molecule has a "seesaw" shape...Ch. 9 - Prob. 2E Ch. 9 - Prob. 3E Ch. 9 - Prob. 4E Ch. 9 - Prob. 5E Ch. 9 - Prob. 6E Ch. 9 - In the hydrocarbon a. What is the hybridization at...Ch. 9 - The drawing below shows the overlap of two hybrid...Ch. 9 - Prob. 9E Ch. 9 - 9.10 The following is part of a molecular...Ch. 9 - Prob. 11E Ch. 9 - Prob. 12E Ch. 9 - 9.13 a. An AB2 molecule is linear. How...Ch. 9 - a. Methane (CH4) and the perchlorate ion (C104-)...Ch. 9 - Prob. 15E Ch. 9 - Prob. 16E Ch. 9 - Prob. 17E Ch. 9 - Prob. 18E Ch. 9 - In which of these molecules or ions does the...Ch. 9 - Prob. 20E Ch. 9 - How many nonbonding electron pairs are there in...Ch. 9 - Prob. 22E Ch. 9 - Prob. 23E Ch. 9 - Prob. 24E Ch. 9 - Give the electron-domain and molecular geometries...Ch. 9 - Prob. 26E Ch. 9 - Prob. 27E Ch. 9 - Prob. 28E Ch. 9 - Prob. 29E Ch. 9 - Prob. 30E Ch. 9 - Ammonia, NH3 reacts with incredibly strong bases...Ch. 9 - In which of the following AFn molecules or ions is...Ch. 9 - a. Explain why BrF4 is square planar, whereas...Ch. 9 - 9.34 Name the proper three-dimensional molecule...Ch. 9 - Prob. 35E Ch. 9 - Prob. 36E Ch. 9 - Prob. 37E Ch. 9 - Prob. 38E Ch. 9 - a. (a) Is the molecule BF3 polar or nonpolar? b....Ch. 9 - Prob. 40E Ch. 9 - Predict whether each of the following molecules is...Ch. 9 - Prob. 42E Ch. 9 - Prob. 43E Ch. 9 - Prob. 44E Ch. 9 - For each statement, irldicate whether it is true...Ch. 9 - Draw sketches illustrating the overlap between the...Ch. 9 - For each statement, indicate whether it is true or...Ch. 9 - Prob. 48E Ch. 9 - Prob. 49E Ch. 9 - Consider the SC12 molecule. a. What IS the...Ch. 9 - Indicate the hybridization of the central atom in...Ch. 9 - Prob. 52E Ch. 9 - Prob. 53E Ch. 9 - Prob. 54E Ch. 9 - Prob. 55E Ch. 9 - Prob. 56E Ch. 9 - a. Draw Lewis structures for ethane (C2He),...Ch. 9 - a. Draw Lewis structures for ethane (C2He),...Ch. 9 - Prob. 59E Ch. 9 - Ethyl acetate. C4H802, is a fragrant substance...Ch. 9 - Prob. 61E Ch. 9 - Prob. 62E Ch. 9 - Prob. 63E Ch. 9 - Prob. 64E Ch. 9 - In the formate ion, HC02- , the carbon atom is the...Ch. 9 - Prob. 66E Ch. 9 - Prob. 67E Ch. 9 - Prob. 68E Ch. 9 - Prob. 69E Ch. 9 - a. If you combine two atomic orbitals on two...Ch. 9 - Prob. 71E Ch. 9 - Prob. 72E Ch. 9 - Prob. 73E Ch. 9 - Indicate whether each statement is true or false....Ch. 9 - Prob. 75E Ch. 9 - Prob. 76E Ch. 9 - Prob. 77E Ch. 9 - Prob. 78E Ch. 9 - Prob. 79E Ch. 9 - Prob. 80E Ch. 9 - Determine the electron configurations for CN+, CN,...Ch. 9 - Prob. 82E Ch. 9 - Consider the molecular orbitals of the P2...Ch. 9 - The iodine bromide molecule, IBr, is an...Ch. 9 - Prob. 85AE Ch. 9 - Prob. 86AE Ch. 9 - Consider the following XF4 ions: PF4, BrF4-,...Ch. 9 - 9.88 Consider the molecule PF4Cl....Ch. 9 - Prob. 89AE Ch. 9 - Fill in the blank spaces in the following chart....Ch. 9 - Prob. 91AE Ch. 9 - Prob. 92AE Ch. 9 - Prob. 93AE Ch. 9 - Prob. 94AE Ch. 9 - Prob. 95AE Ch. 9 - Prob. 96AE Ch. 9 - Prob. 97AE Ch. 9 - Prob. 98AE Ch. 9 - Prob. 99AE Ch. 9 - Prob. 100AE Ch. 9 - In ozone, 03, the two oxygen atoms on the ends Of...Ch. 9 - Butadiene, C4H6, is a planar molecule that has the...Ch. 9 - The structure of borazine, B3N3H6, is a...Ch. 9 - Prob. 104AE Ch. 9 - Prob. 105AE Ch. 9 - Prob. 106AE Ch. 9 - Prob. 107AE Ch. 9 - Prob. 108AE Ch. 9 - Azo dyes are organic dyes that are used for many...Ch. 9 - a. Using only the valence atomic orbitals of a...Ch. 9 - Carbon monoxide, CO, is isoelectronic to N2. a....Ch. 9 - The energy-level diagram in Figure 9.36 shows that...Ch. 9 - A compound composed of 2.1 29.8%N, and 68.1%O has...Ch. 9 - 9.114 Sulfur tetrafluoride (SR4) reacts slowly...Ch. 9 - Prob. 115IE Ch. 9 - The molecule 2-butene, C4Hs, can undergo a...Ch. 9 - Prob. 117IE Ch. 9 - Use average bond enthalpies (Table 8.3 ) to...Ch. 9 - Prob. 119IE Ch. 9 - Prob. 120IE Ch. 9 - Prob. 121IE Ch. 9 - Prob. 122IE

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.