Chapter 8.6, Problem 29PPS

To determine

To calculate:

The width of the mouth of the tornado of given diagram.

Answer to Problem 29PPS

The width of the mouth of the tornado is about $126.2$ ft.

Explanation of Solution

Given information:

  

Concept used:

Law of sines:

  $a=b\frac{\sin \alpha }{\sin \beta }$

Where,

  $b=$ side

Calculation:

  

With the help of the above diagram it is get that having the two sides and a nonincluded sides, use the law of the sines to set up a proportion.

Law of sines:

  $a=b\frac{\sin \alpha }{\sin \beta }$

First substitute and then simplify,

  $\frac{\sin 26}{x}=\frac{\sin 44}{200}$

Now use the cross products property,

  $x.\sin 44=200.\sin 26$

Bow divide each side by sin $44$

  $x=\frac{200\sin 26}{\sin 44}$

Now, the value of $x$ is,

  $x\approx 126.2$

Hence, the mouth of the tornado is about $126.2$ ft.