Chapter 8, Problem 13SGR

To determine

The geometric mean of the given terms.

Answer to Problem 13SGR

  $\frac{8}{3}$

Explanation of Solution

Given:

The given terms are:

  $\frac{8\sqrt{2}}{3}\text{and }\frac{4\sqrt{2}}{3}$

Calculation:

The geometric mean of the given terms will be:

  $\begin{array}{l}=\sqrt{\left(\frac{8\sqrt{2}}{3}\right)\left(\frac{4\sqrt{2}}{3}\right)}\\ =\sqrt{\frac{32\sqrt{4}}{9}}\\ =\sqrt{\frac{32\left(2\right)}{9}}\\ =\sqrt{\frac{64}{9}}\\ =\frac{8}{3}\end{array}$