Chapter 8.3, Problem 61SR

To determine

The matrix after the operation.

Answer to Problem 61SR

  $\left[\begin{array}{ccc}12& -9& 12\\ 1& -3& -10\end{array}\right]$

Explanation of Solution

Given:

The given equation is:

  $\left[\begin{array}{ccc}10& 0& 8\\ 2& -5& -7\end{array}\right]+\left[\begin{array}{ccc}2& -9& 4\\ -1& 2& -3\end{array}\right]$

Calculation:

The solution can be obtained as:

  $\begin{array}{l}=\left[\begin{array}{ccc}10& 0& 8\\ 2& -5& -7\end{array}\right]+\left[\begin{array}{ccc}2& -9& 4\\ -1& 2& -3\end{array}\right]\\ =\left[\begin{array}{ccc}10+2& 0-9& 8+4\\ 2-1& -5+2& -7-3\end{array}\right]\\ =\left[\begin{array}{ccc}12& -9& 12\\ 1& -3& -10\end{array}\right]\end{array}$