Chapter 8, Problem 16PT

To determine

To Find: Solve the given equation and verify the solution

Answer to Problem 16PT

The solution of the equation $a^2=12a$ are $a=0$ and $a=12$

  $a=0$ is a solution of the equation $a^2=12a$

  $a=12$ is a solution of the equation $a^2=12a$

Explanation of Solution

Given information:

Equation is $a^2=12a$

Calculation:

Calculation:

The equation can be solved as below:

  $a^2=12a$

  $a^2-12a=0$

  $a(a-12)=0$

  $a=0a=12$

Check:

Put $a=0$ in the equation

  $0^2=12\ast 0$

  $0=0$

Again put $a=12$ in equation

  ${12}^2={12}^{\ast }12$

  $144=144$

Hence the solutions are correct