Chapter 8.3, Problem 13PPS

To determine

To calculate:To complete the below table and find four solutions for the below equation and to write the solutions as ordered pair −

  $y=-2x$

$x$	$y=-2x$	$y$
$-1$
$0$
$1$
$2$

Answer to Problem 13PPS

The completed table is :

$x$	$y=-2x$	$y$
$-1$	$y=-2\left(-1\right)$	$2$
$0$	$y=-2\left(0\right)$	$0$
$1$	$y=-2\left(1\right)$	$-2$
$2$	$y=-2\left(2\right)$	$-4$

The four solutions as ordered pairs are $\left(-1,2\right)$ , $\left(0,0\right)$ , $\left(1,-2\right)$ and $\left(2,-4\right)$ .

Explanation of Solution

Given information:

Equation is $y=-2x$

Formula Used:

To solve an equation with multiple variables, we need to consider some random values for one of the variables and solve for the other one to find the ordered pair.

Calculation:

Given equation is $y=-2x$

Using the above explanation, we have -

Let the value of $x$ be $-1$ , substituting the value of $x$ in the above equation, we have:

  $y=-2\left(-1\right)$

Solving the above equation, we have :

  $y=2$

Thus, the first ordered pair is $\left(-1,2\right)$ .

Using the same approach to find the other ordered pairs −

Let the value of $x$ be $0$ , substituting the value of $x$ in the above equation, we have:

  $y=-2\left(0\right)$

Solving the above equation, we have :

  $y=0$

Thus, the second ordered pair is $\left(0,0\right)$ .

Let the value of $x$ be $1$ , substituting the value of $x$ in the above equation, we have:

  $y=-2\left(1\right)$

Solving the above equation, we have :

  $y=-2$

Thus, the third ordered pair is $\left(1,-2\right)$ .

Let the value of $x$ be $2$ , substituting the value of $x$ in the above equation, we have:

  $y=-2\left(2\right)$

Solving the above equation, we have :

  $y=-4$

Thus, the fourth ordered pair is $\left(2,-4\right)$ .

The completed table is :

$x$	$y=-2x$	$y$
$-1$	$y=-2\left(-1\right)$	$2$
$0$	$y=-2\left(0\right)$	$0$
$1$	$y=-2\left(1\right)$	$-2$
$2$	$y=-2\left(2\right)$	$-4$

Thus, the four ordered pairs are $\left(-1,2\right)$ , $\left(0,0\right)$ , $\left(1,-2\right)$ and $\left(2,-4\right)$ .