Chapter 8.10, Problem 30STP

To determine

The correct option which represent the number of pictures taken by each person when the Jennifer has 16 times lesser than Amy and Amy has taken the three times pictures as Jennifer.

A. $\begin{array}{l}a=3j\\ a=j+16\end{array}$

B. $\begin{array}{l}a=3j\\ a=j-16\end{array}$

C. $\begin{array}{l}j=3a\\ j=a+16\end{array}$

D. $\begin{array}{l}j=3a\\ j=a-16\end{array}$

Answer to Problem 30STP

The correct option is A. $\begin{array}{l}a=3j\\ a=j+16\end{array}$

Explanation of Solution

Given:

Two conditions given:

Jennifer has 16 times lesser than Amy.

Amy has taken the three times pictures as Jennifer.

Calculation:

Now, the given condition written in the form eqn:

  $a=3j$....... (1)

  $j=a-16$....... (2)

Where,

Amy: $a$

Jennifer: $j$

The second eq. can be rewritten as:

  $a=j+16$

So, the system of eqn. is to satisfy the two problem conditions are:

  $\begin{array}{l}a=3j\\ a=j+16\end{array}$

Conclusion:

Hence, the correct option is A.