Chapter 8.2, Problem 6PSA

a

To determine

To find:The mean proportion of pair of given extremes i.e. 4 and 25.

Answer to Problem 6PSA

The mean proportion of given extremes is = 10

Explanation of Solution

Given information Pair of extremes as 4 and 25

Formula used

Mean proportion = $\sqrt{\text{Product of extremes}}$

CalculationMean proportion = $\sqrt{\text{Product of extremes}}$

  $\therefore$ we have,

Mean proportion = $\sqrt{4\times 25}=\sqrt{100}=10$

b

To determine

To find:The mean proportion of pair of given extremes i.e. 2 and 5.

Answer to Problem 6PSA

The mean proportion of given extremes is = $\sqrt{10}$

Explanation of Solution

Given information Pair of extremes as 2 and 5

Formula used

Mean proportion = $\sqrt{\text{Product of extremes}}$

CalculationMean proportion = $\sqrt{\text{Product of extremes}}$

  $\therefore$ we have,

Mean proportion = $\sqrt{2\times 5}=\sqrt{10}$