
The first 10 partial sums, the graph of the sequence of the terms and the sequence of the partial sums and determine if the series is convergent or divergent and hence find the sum of the series.

Answer to Problem 5E
The first 10 partial sums are: 0.44721 , 1.15432 , 1.98637 , 2.88080 , 3.80927 , 4.75796 , 5.71948 , 6.68962 , 7.66581 and 8.64639 .
The given series is divergent.
Explanation of Solution
Given: The given series is ∞∑n=1n√n2+4 .
Concepts Used: Let ∞∑n=1an be any series. Then the nth partial sum of the series is given by-
sn=n∑k=1ak=a1+a2+....+an
If the sequence {sn} is convergent and limn→∞sn=s as a real number, then the series ∞∑n=1an is convergent and the sum of the series is equal to s , i.e.-
∞∑n=1an=s
If the sequence {sn} is divergent, then the series is also divergent.
Also, if limn→∞an doesn’t exist or if limn→∞an≠0 , then also the series ∞∑n=1an is divergent.
Calculations: The first 10 terms of the given sequence are as follows-
a1=0.447214
a2=0.707107
a3=0.832050
a4=0.894427
a5=0.928477
a6=0.948683
a7=0.961524
a8=0.970143
a9=0.976187
a10=0.980581
The first 10 partial sums are as follows-
s1=1∑n=1n√n2+4=0.44721
s2=2∑n=1n√n2+4=1.15432
s3=3∑n=1n√n2+4=1.98637
s4=4∑n=1n√n2+4=2.88080
s5=5∑n=1n√n2+4=3.80927
s6=6∑n=1n√n2+4=4.75796
s7=7∑n=1n√n2+4=5.71948
s8=8∑n=1n√n2+4=6.68962
s9=9∑n=1n√n2+4=7.66581
s10=10∑n=1n√n2+4=8.64639
Hence, the graph of the terms of the sequence of the partial sums of the sequence is given by-
Now,
limn→∞an=limn→∞n√n2+4
=limn→∞1√n2+4n
=limn→∞1√n2+4n2
=limn→∞1√1+4n2
=1 (Since limn→∞4n2=0 )
Since, limn→∞an≠0 , thus, the given series is divergent.
Chapter 8 Solutions
Single Variable Calculus: Concepts and Contexts, Enhanced Edition
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