
a.
To write: the equations that represents the height h (in feet) as a function of time t (in seconds) for both the acorns.
a.

Answer to Problem 39E
Acorn 1: h=−16t2+45
Acorn 2: h=−16t2+32
Explanation of Solution
Given information:
The first acorn falls 45 feet.
The second acorn falls 32 feet.
Concept used:
The height (in feet) of a falling object t seconds after it is dropped from an initial height of s0 (in feet) is given by the function:
h(t)=−16t2+s0 ..... (1)
Calculation:
The height h (in feet) for the first acorn as a function of time t (in seconds) is found by substituting s0=45 in equation (1),
h=−16t2+45
The height h (in feet) for the second acorn as a function of time t (in seconds) is found by substituting s0=32 in equation (1),
h=−16t2+32
b.
To describe: how graphs of the two equations are related.
b.

Answer to Problem 39E
The graph which represents the height of the first acorn is a vertical translation 13 units up of the graph representing the height of the second acorn.
Explanation of Solution
Given information:
The equations that represents the height h (in feet) as a function of time t (in seconds) for both the acorns are:
Acorn 1: h1=−16t2+45
Acorn 2: h2=−16t2+32
Concept used:
Vertical translation:
The graph of g(x)=f(x)+k is a vertical translation of the graph of f .
The vertical shift is k units up if k>0 and k units down if k<0 .
Consider the equation representing the height of first acorn:
h1=−16t2+45=−16t2+32+13=h2+13
It can be observed that h1(t)=h2(t)+13
So, the graph of h1 is a vertical translation of the graph of h2 .
Now, as 13>0 the shift is 13 units up and so the graph which represents the height of the first acorn is a vertical translation 13 units up of the graph representing the height of the second acorn.
Chapter 8 Solutions
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