Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
2nd Edition
ISBN: 9780076602919
Author: McGraw-Hill Education
Publisher: McGraw-Hill Education
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Chapter 8.1, Problem 70PFA

a.

To determine

To write an expression for the perimeter of rectangle on the left.

a.

Expert Solution
Check Mark

Answer to Problem 70PFA

  P=8x+8

Explanation of Solution

Given:

  Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1), Chapter 8.1, Problem 70PFA , additional homework tip  1

Formula used:

Perimeter of rectangle =2(l+b)

where l is the length of the rectangle and b is the breadth of the rectangle.

Calculation:

The length of the rectangle in the left is 3x+4.

  l=3x+4

The breadth of the rectangle in the left is x.

  b=x

Substituting the length and breadth of the rectangle in the formula of the perimeter,

  P=2(l+b)P=2((3x+4)+x)P=2(3x+4+x)P=2(4x+4)P=8x+8

Conclusion:

Therefore, the perimeter of the rectangle is 8x+8 .

b.

To determine

To write an expression for the perimeter of rectangle on the right.

b.

Expert Solution
Check Mark

Answer to Problem 70PFA

  P=4x2+8x+12

Explanation of Solution

Given:

  Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1), Chapter 8.1, Problem 70PFA , additional homework tip  2

Formula used:

Perimeter of rectangle =2(l+b)

where l is the length of the rectangle and b is the breadth of the rectangle.

Calculation:

The length of the rectangle in the right is 2x2+3x+6.

  l=2x2+3x+6

The breadth of the rectangle in the right is x.

  b=x

Substituting the length and breadth of the rectangle in the formula of the perimeter,

  P=2(l+b)P=2((2x2+3x+6)+x)P=2(2x2+3x+6+x)P=2(2x2+4x+6)P=4x2+8x+12

Conclusion:

Therefore, the perimeter of the rectangle is 4x2+8x+12 .

c.

To determine

To write an expression for the total perimeter of both the triangles.

c.

Expert Solution
Check Mark

Answer to Problem 70PFA

  P=4x2+16x+20

Explanation of Solution

Given:

From subpart (a),

  P=8x+8

From subpart (b),

  P=4x2+8x+12

Concept used:

To find the total perimeter of two rectangles, add both the perimeters.

Calculation:

The total perimeter of both the rectangles is,

  P=(8x+8)+(4x2+8x+12)P=8x+8+4x2+8x+12

Combining the like terms,

  P=4x2+(8x+8x)+(12+8)P=4x2+16x+20

Conclusion:

The total perimeter of both the rectangles is 4x2+16x+20.

d.

To determine

To find the perimeter of the rectangle by joining length of both the rectangles whose width is x .

d.

Expert Solution
Check Mark

Answer to Problem 70PFA

  4x2+14x+20

Explanation of Solution

Given:

  Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1), Chapter 8.1, Problem 70PFA , additional homework tip  3

Formula Used:

Perimeter of the rectangle =2(l+b)

where l is the length of the rectangle and b is the breadth of the rectangle.

Calculation:

The total length of the rectangle is the total of the length of both the rectangles.

  (3x+4)+(2x2+3x+6)3x+4+2x2+3x+6

Combining the like terms,

  2x2+(3x+3x)+(6+4)2x2+6x+10

The length of new rectangle is 2x2+6x+10

Width of the rectangle is x .

  Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1), Chapter 8.1, Problem 70PFA , additional homework tip  4

Therefore, the perimeter of the rectangle is,

  P=2(l+b)=2((2x2+6x+10)+x)=2(2x2+6x+10+x)=2(2x2+7x+10)=4x2+14x+20

Conclusion:

The perimeter of both the rectangle is 4x2+14x+20.

e.

To determine

To check if the perimeter of both the rectangles same as the perimeter of the combined rectangles.

e.

Expert Solution
Check Mark

Answer to Problem 70PFA

The perimeters are different.

Explanation of Solution

Given:

From subpart (c),

  P=4x2+16x+20.

From subpart (d),

  P=4x2+14x+20

Comparing the perimeters in both subpart (c) and subpart (d),

The perimeters are different.

Conclusion:

Therefore, the perimeters are different.

f.

To determine

To calculator of the perimeter of the new rectangle if x=1.5 cm

f.

Expert Solution
Check Mark

Answer to Problem 70PFA

  P=50cm

Explanation of Solution

Given:

From subpart (d),

  P=4x2+14x+20

  x=1.5

Calculation:

Substituting x=1.5 in P=4x2+14x+20 ,

   P=4 (1.5) 2 +14(1.5)+20P=4(2.25)+14(1.5)+20P=9+21+20P=50

Conclusion:

Therefore, the perimeter of the new triangle is 50 cm if x = 1.5 cm.

Chapter 8 Solutions

Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)

Ch. 8.1 - Prob. 1CYUCh. 8.1 - Prob. 2CYUCh. 8.1 - Prob. 3CYUCh. 8.1 - Prob. 4CYUCh. 8.1 - Prob. 5CYUCh. 8.1 - Prob. 6CYUCh. 8.1 - Prob. 7CYUCh. 8.1 - Prob. 8CYUCh. 8.1 - Prob. 9CYUCh. 8.1 - Prob. 10CYUCh. 8.1 - Prob. 11CYUCh. 8.1 - Prob. 12CYUCh. 8.1 - Prob. 13CYUCh. 8.1 - Prob. 14CYUCh. 8.1 - Prob. 15CYUCh. 8.1 - Prob. 16CYUCh. 8.1 - Prob. 17CYUCh. 8.1 - Prob. 18CYUCh. 8.1 - Prob. 19CYUCh. 8.1 - Prob. 20PPSCh. 8.1 - Prob. 21PPSCh. 8.1 - Prob. 22PPSCh. 8.1 - Prob. 23PPSCh. 8.1 - Prob. 24PPSCh. 8.1 - Prob. 25PPSCh. 8.1 - Prob. 26PPSCh. 8.1 - Prob. 27PPSCh. 8.1 - Prob. 28PPSCh. 8.1 - Prob. 29PPSCh. 8.1 - Prob. 30PPSCh. 8.1 - Prob. 31PPSCh. 8.1 - Prob. 32PPSCh. 8.1 - Prob. 33PPSCh. 8.1 - Prob. 34PPSCh. 8.1 - Prob. 35PPSCh. 8.1 - Prob. 36PPSCh. 8.1 - Prob. 37PPSCh. 8.1 - Prob. 38PPSCh. 8.1 - Prob. 39PPSCh. 8.1 - Prob. 40PPSCh. 8.1 - Prob. 41PPSCh. 8.1 - Prob. 42PPSCh. 8.1 - Prob. 43PPSCh. 8.1 - Prob. 44PPSCh. 8.1 - Prob. 45PPSCh. 8.1 - Prob. 46PPSCh. 8.1 - Prob. 47PPSCh. 8.1 - Prob. 48PPSCh. 8.1 - Prob. 49PPSCh. 8.1 - Prob. 50PPSCh. 8.1 - Prob. 51PPSCh. 8.1 - Prob. 52PPSCh. 8.1 - Prob. 53PPSCh. 8.1 - Prob. 54PPSCh. 8.1 - Prob. 55PPSCh. 8.1 - Prob. 56PPSCh. 8.1 - Prob. 57PPSCh. 8.1 - Prob. 58PPSCh. 8.1 - Prob. 59PPSCh. 8.1 - Prob. 60PPSCh. 8.1 - Prob. 61HPCh. 8.1 - Prob. 62HPCh. 8.1 - Prob. 63HPCh. 8.1 - Prob. 64HPCh. 8.1 - Prob. 65HPCh. 8.1 - Prob. 66PFACh. 8.1 - Prob. 67PFACh. 8.1 - Prob. 68PFACh. 8.1 - Prob. 69PFACh. 8.1 - Prob. 70PFACh. 8.1 - Prob. 71PFACh. 8.1 - Prob. 72PFACh. 8.2 - Prob. 1AGPCh. 8.2 - Prob. 1BGPCh. 8.2 - Prob. 2AGPCh. 8.2 - Prob. 2BGPCh. 8.2 - Prob. 3GPCh. 8.2 - Prob. 4AGPCh. 8.2 - Prob. 4BGPCh. 8.2 - Prob. 1CYUCh. 8.2 - Prob. 2CYUCh. 8.2 - Prob. 3CYUCh. 8.2 - Prob. 4CYUCh. 8.2 - Prob. 5CYUCh. 8.2 - Prob. 6CYUCh. 8.2 - Prob. 7CYUCh. 8.2 - Prob. 8CYUCh. 8.2 - Prob. 9CYUCh. 8.2 - Prob. 10CYUCh. 8.2 - Prob. 11CYUCh. 8.2 - Prob. 12CYUCh. 8.2 - Prob. 13CYUCh. 8.2 - Prob. 14CYUCh. 8.2 - Prob. 15CYUCh. 8.2 - Prob. 16CYUCh. 8.2 - Prob. 17CYUCh. 8.2 - Prob. 18PPSCh. 8.2 - 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Prob. 55HPCh. 8.5 - Prob. 56HPCh. 8.5 - Prob. 57PFACh. 8.5 - Prob. 58PFACh. 8.5 - Prob. 59PFACh. 8.5 - Prob. 60PFACh. 8.5 - Prob. 61PFACh. 8.5 - Prob. 62PFACh. 8.5 - Prob. 63PFACh. 8.5 - Prob. 64PFACh. 8.5 - Prob. 65PFACh. 8.6 - Prob. 1AGPCh. 8.6 - Prob. 1BGPCh. 8.6 - Prob. 2AGPCh. 8.6 - Prob. 2BGPCh. 8.6 - Prob. 3AGPCh. 8.6 - Prob. 3BGPCh. 8.6 - Prob. 4AGPCh. 8.6 - Prob. 4BGPCh. 8.6 - Prob. 5AGPCh. 8.6 - Prob. 5BGPCh. 8.6 - Prob. 6AGPCh. 8.6 - Prob. 6BGPCh. 8.6 - Prob. 1CYUCh. 8.6 - Prob. 2CYUCh. 8.6 - Prob. 3CYUCh. 8.6 - Prob. 4CYUCh. 8.6 - Prob. 5CYUCh. 8.6 - Prob. 6CYUCh. 8.6 - Prob. 7CYUCh. 8.6 - Prob. 8CYUCh. 8.6 - Prob. 9CYUCh. 8.6 - Prob. 10CYUCh. 8.6 - Prob. 11PPSCh. 8.6 - Prob. 12PPSCh. 8.6 - Prob. 13PPSCh. 8.6 - Prob. 14PPSCh. 8.6 - Prob. 15PPSCh. 8.6 - Prob. 16PPSCh. 8.6 - Prob. 17PPSCh. 8.6 - Prob. 18PPSCh. 8.6 - Prob. 19PPSCh. 8.6 - Prob. 20PPSCh. 8.6 - Prob. 21PPSCh. 8.6 - Prob. 22PPSCh. 8.6 - Prob. 23PPSCh. 8.6 - Prob. 24PPSCh. 8.6 - Prob. 25PPSCh. 8.6 - Prob. 26PPSCh. 8.6 - Prob. 27PPSCh. 8.6 - Prob. 28PPSCh. 8.6 - Prob. 29PPSCh. 8.6 - Prob. 30PPSCh. 8.6 - Prob. 31PPSCh. 8.6 - Prob. 32PPSCh. 8.6 - Prob. 33PPSCh. 8.6 - Prob. 34PPSCh. 8.6 - Prob. 35PPSCh. 8.6 - Prob. 36PPSCh. 8.6 - Prob. 37PPSCh. 8.6 - Prob. 38PPSCh. 8.6 - Prob. 39PPSCh. 8.6 - Prob. 40PPSCh. 8.6 - Prob. 41PPSCh. 8.6 - Prob. 42PPSCh. 8.6 - Prob. 43PPSCh. 8.6 - Prob. 44HPCh. 8.6 - Prob. 45HPCh. 8.6 - Prob. 46HPCh. 8.6 - Prob. 47HPCh. 8.6 - Prob. 48HPCh. 8.6 - Prob. 49HPCh. 8.6 - Prob. 50HPCh. 8.6 - Prob. 51HPCh. 8.6 - Prob. 52HPCh. 8.6 - Prob. 53HPCh. 8.6 - Prob. 54PFACh. 8.6 - Prob. 55PFACh. 8.6 - Prob. 56PFACh. 8.6 - Prob. 57PFACh. 8.6 - Prob. 58PFACh. 8.6 - Prob. 59PFACh. 8.6 - Prob. 60PFACh. 8.6 - Prob. 61PFACh. 8.6 - Prob. 62PFACh. 8.7 - Prob. 1AGPCh. 8.7 - Prob. 1BGPCh. 8.7 - Prob. 1CGPCh. 8.7 - Prob. 1DGPCh. 8.7 - Prob. 2AGPCh. 8.7 - Prob. 2BGPCh. 8.7 - Prob. 3GPCh. 8.7 - Prob. 4AGPCh. 8.7 - Prob. 4BGPCh. 8.7 - Prob. 5AGPCh. 8.7 - Prob. 5BGPCh. 8.7 - Prob. 5CGPCh. 8.7 - Prob. 5DGPCh. 8.7 - 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Prob. 50HPCh. 8.7 - Prob. 51HPCh. 8.7 - Prob. 52HPCh. 8.7 - Prob. 53HPCh. 8.7 - Prob. 54PFACh. 8.7 - Prob. 55PFACh. 8.7 - Prob. 56PFACh. 8.7 - Prob. 57PFACh. 8.7 - Prob. 58PFACh. 8.7 - Prob. 59PFACh. 8.7 - Prob. 60PFACh. 8.7 - Prob. 61PFACh. 8.7 - Prob. 62PFACh. 8 - Prob. 1MCQCh. 8 - Prob. 2MCQCh. 8 - Prob. 3MCQCh. 8 - Prob. 4MCQCh. 8 - Prob. 5MCQCh. 8 - Prob. 6MCQCh. 8 - Prob. 7MCQCh. 8 - Prob. 8MCQCh. 8 - Prob. 9MCQCh. 8 - Prob. 10MCQCh. 8 - Prob. 11MCQCh. 8 - Prob. 12MCQCh. 8 - Prob. 13MCQCh. 8 - Prob. 14MCQCh. 8 - Prob. 15MCQCh. 8 - Prob. 16MCQCh. 8 - Prob. 17MCQCh. 8 - Prob. 18MCQCh. 8 - Prob. 19MCQCh. 8 - Prob. 20MCQCh. 8 - Prob. 21MCQCh. 8 - Prob. 22MCQCh. 8 - Prob. 23MCQCh. 8 - Prob. 24MCQCh. 8 - Prob. 25MCQCh. 8 - Prob. 26MCQCh. 8 - Prob. 27MCQCh. 8 - Prob. 28MCQCh. 8 - Prob. 29MCQCh. 8 - Prob. 30MCQCh. 8 - Prob. 31MCQCh. 8 - Prob. 32MCQCh. 8 - Prob. 33MCQCh. 8 - Prob. 34MCQCh. 8 - Prob. 1SGRCh. 8 - Prob. 2SGRCh. 8 - Prob. 3SGRCh. 8 - Prob. 4SGRCh. 8 - Prob. 5SGRCh. 8 - Prob. 6SGRCh. 8 - Prob. 7SGRCh. 8 - Prob. 8SGRCh. 8 - Prob. 9SGRCh. 8 - Prob. 10SGRCh. 8 - Prob. 11SGRCh. 8 - Prob. 12SGRCh. 8 - Prob. 13SGRCh. 8 - Prob. 14SGRCh. 8 - Prob. 15SGRCh. 8 - Prob. 16SGRCh. 8 - Prob. 17SGRCh. 8 - Prob. 18SGRCh. 8 - Prob. 19SGRCh. 8 - Prob. 20SGRCh. 8 - Prob. 21SGRCh. 8 - Prob. 22SGRCh. 8 - Prob. 23SGRCh. 8 - Prob. 24SGRCh. 8 - Prob. 25SGRCh. 8 - Prob. 26SGRCh. 8 - Prob. 27SGRCh. 8 - Prob. 28SGRCh. 8 - Prob. 29SGRCh. 8 - Prob. 30SGRCh. 8 - Prob. 31SGRCh. 8 - Prob. 32SGRCh. 8 - Prob. 33SGRCh. 8 - Prob. 34SGRCh. 8 - Prob. 35SGRCh. 8 - Prob. 36SGRCh. 8 - Prob. 37SGRCh. 8 - Prob. 38SGRCh. 8 - Prob. 39SGRCh. 8 - Prob. 40SGRCh. 8 - Prob. 41SGRCh. 8 - Prob. 42SGRCh. 8 - Prob. 43SGRCh. 8 - Prob. 44SGRCh. 8 - Prob. 45SGRCh. 8 - Prob. 46SGRCh. 8 - Prob. 47SGRCh. 8 - Prob. 48SGRCh. 8 - Prob. 49SGRCh. 8 - Prob. 50SGRCh. 8 - Prob. 51SGRCh. 8 - Prob. 52SGRCh. 8 - Prob. 53SGRCh. 8 - Prob. 54SGRCh. 8 - Prob. 55SGRCh. 8 - Prob. 56SGRCh. 8 - Prob. 57SGRCh. 8 - Prob. 58SGRCh. 8 - Prob. 59SGRCh. 8 - Prob. 60SGRCh. 8 - Prob. 61SGRCh. 8 - Prob. 62SGRCh. 8 - Prob. 63SGRCh. 8 - Prob. 64SGRCh. 8 - Prob. 65SGRCh. 8 - Prob. 66SGRCh. 8 - Prob. 67SGRCh. 8 - Prob. 68SGRCh. 8 - Prob. 69SGRCh. 8 - Prob. 70SGRCh. 8 - Prob. 71SGRCh. 8 - Prob. 72SGRCh. 8 - Prob. 73SGRCh. 8 - Prob. 74SGRCh. 8 - Prob. 75SGRCh. 8 - Prob. 76SGRCh. 8 - Prob. 77SGRCh. 8 - Prob. 78SGRCh. 8 - Prob. 79SGRCh. 8 - Prob. 80SGRCh. 8 - Prob. 81SGRCh. 8 - Prob. 1PTCh. 8 - Prob. 2PTCh. 8 - Prob. 3PTCh. 8 - Prob. 4PTCh. 8 - Prob. 5PTCh. 8 - Prob. 6PTCh. 8 - Prob. 7PTCh. 8 - Prob. 8PTCh. 8 - Prob. 9PTCh. 8 - Prob. 10PTCh. 8 - Prob. 11PTCh. 8 - Prob. 12PTCh. 8 - Prob. 13PTCh. 8 - Prob. 14PTCh. 8 - Prob. 15PTCh. 8 - Prob. 16PTCh. 8 - Prob. 17PTCh. 8 - Prob. 18PTCh. 8 - Prob. 19PTCh. 8 - Prob. 20PTCh. 8 - Prob. 21PTCh. 8 - Prob. 22PTCh. 8 - Prob. 23PTCh. 8 - Prob. 24PTCh. 8 - Prob. 25PTCh. 8 - Prob. 26PTCh. 8 - Prob. 27PTCh. 8 - Prob. 28PTCh. 8 - Prob. 29PTCh. 8 - Prob. 30PTCh. 8 - Prob. 31PTCh. 8 - Prob. 32PTCh. 8 - Prob. 33PTCh. 8 - Prob. 1CRCh. 8 - Prob. 2CRCh. 8 - Prob. 3CRCh. 8 - Prob. 4CRCh. 8 - Prob. 5CRCh. 8 - Prob. 6CRCh. 8 - Prob. 7CRCh. 8 - Prob. 8CRCh. 8 - Prob. 9CRCh. 8 - Prob. 10CRCh. 8 - Prob. 11CRCh. 8 - Prob. 12CRCh. 8 - Prob. 13CR
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