Chapter 8, Problem 26MCQ

To determine

To find the product of given two polynomials.

Answer to Problem 26MCQ

  $16d^3+2d^2+5d-3$

Explanation of Solution

Given:

  $\left(8d-3\right)\left(2d^2+d+1\right)$

Formula used:

Distributive Law:

  $x\left(y\pm z\right)=x\cdot y\pm x\cdot z$

Calculation:

Consider the given expression,

  $\Rightarrow \left(8d-3\right)\left(2d^2+d+1\right)$

  $\Rightarrow 8d\cdot 2d^2+8d\cdot d+8d\cdot 1-3\cdot 2d^2-3\cdot d-3\cdot 1$   [ $\because$$x\left(y\pm z\right)=x\cdot y\pm x\cdot z$ ]

  $\begin{array}{l}\Rightarrow 16d^3+8d^2+8d-6d^2-3d-3\\ \Rightarrow 16d^3+8d^2-6d^2+8d-3d-3\\ \Rightarrow 16d^3+2d^2+5d-3\end{array}$

Conclusion:

Therefore, product of the given polynomials is $16d^3+2d^2+5d-3$ .