Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 8, Problem 8.8P
To determine
Plot the variation of total stress, effective stress, and pore water pressure with depth.
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For the soil profile shown below, the piezometer reading is 1 m above the W.T level calculate
the total and effective stress (vertical and horizontal) at points A and B. Use ko
= 0.5
N.G.L
W. T
I m
Piezometer
5 m
A
y = 15.9 kN/m³
Clay
Ysat = 14.4 kN/m³
B
Sand under artesian pressure
0.45 m
7.55 m
7.55 m
Answer in three decimal places please
Refer to the soil profile shown. Given H1 = 8.42 m., and H2 = 5.21 m. If the ground water table rises by 3 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer. Properties of dry sand: Gs = 2.54, e = 0.61. Properties of clay: Gs = 2.76, e = 0.86. Round off to two decimal places.
Chapter 8 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
Ch. 8 - Prob. 8.1PCh. 8 - Prob. 8.2PCh. 8 - Prob. 8.3PCh. 8 - Prob. 8.4PCh. 8 - Prob. 8.5PCh. 8 - Prob. 8.6PCh. 8 - Prob. 8.7PCh. 8 - Prob. 8.8PCh. 8 - Prob. 8.9PCh. 8 - The soil profile at a site consists of 10 m of...
Ch. 8 - Prob. 8.11PCh. 8 - Prob. 8.12PCh. 8 - Prob. 8.13PCh. 8 - Prob. 8.14PCh. 8 - A sand has Gs = 2.66. Calculate the hydraulic...Ch. 8 - Prob. 8.16PCh. 8 - A point load of 1000 kN is applied at the ground...Ch. 8 - Point loads of magnitude 9, 18, and 27 kN act at...Ch. 8 - Refer to Figure 8.13. The magnitude of the line...Ch. 8 - Refer to Figure 8.24. Determine the vertical...Ch. 8 - Consider a circularly loaded flexible area on the...Ch. 8 - A flexible circular footing of radius R carries a...Ch. 8 - The plan of a flexible rectangular loaded area is...Ch. 8 - Refer to Figure 8.26. The circular flexible area...Ch. 8 - Refer to Figure 8.27. The flexible area is...Ch. 8 - Prob. 8.26CTPCh. 8 - Prob. 8.27CTP
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- Answer in three decimal places pleasearrow_forwardQuestion 1: (10) For the soil profile shown below where H1 = 5 m and H2 = 5 m: a) Calculate the total stress (o), pore water pressure (u), and effective stress (o') at point A. b) In order to decrease the effective stress at point A by 15 kN/m2, what would be the depth of the water table from the ground surface. XXXX H1 Dry Sand e = 0.60 G, = 2.68 Clay H2 e 0.80 G = 2.75 %3D %23arrow_forwardRefer to the soil profile shown. Given H1 = 9.89 m., and H2 = 5.80 m. If the ground water table rises by 3.78 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer. Properties of dry sand: Gs = 2.53, e = 0.63. Properties of clay: Gs = 2.75, e = 0.81arrow_forward
- 1.A dry sand is known to have an angle of internal friction of 29. A triaxial test is planned, where the confining pressure will be 41 kPa. What is the maximum axial stress, in kPa, (major principal stress) that can be applied? Calculate the value to 1 decimal place. Do not provide units in your answer. 2.A clay soil is subjected to a triaxial test under unconsolidated-undrained conditions. At failure, the major and minor principal stresses are 8401 psf and 4875 psf, respectively. What is the shear strength of this soil if the confining pressure is doubled? Provide your answer in psf with no decimals.arrow_forwardPlease show the solution.arrow_forwardQuestion 33 Dry Sand H, Groundwater Table Clay H, Refer to the soil profile shown. Given H1 = 9.89 m., and H2 = 5.8 m. If the ground water table rises by 3.78 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer. Properties of dry sand: Gs = 2.53, e = 0.63. Properties of clay: Gs = 2.75, e = 0.81. Round off to two decimal places.arrow_forward
- Given H1 = 8.3 m., and H2 = 4.43 m. If the ground water table rises by 2.29 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer. Properties of dry sand: Gs = 2.59, e = 0.61. Properties of clay: Gs = 2.74, e = 0.86. Round off to two decimal places. Answer: 13.95arrow_forwardCalculate the effective stress, neutral stress, and total stress at points A & B in the image belowarrow_forwardRefer to the soil profile shown. Given H1 = 8.3 m., and H2 = 4.43 m. If the ground water table rises by 2.29 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer. Properties of dry sand: Gs = 2.59, e = 0.61. Properties of clay: Gs = 2.74, e = 0.86. Round off to two decimal places.arrow_forward
- Dry Sand H, Groundwater Table Clay H2 Refer to the soil profile shown. Given H1 = 9.48 m., and H2 = 4.41 m. If the ground water table rises by 2.94 meters, determine the change in effective stress (numerical value only, in kPa) at the bottom of the clay layer. Properties of dry sand: Gs = 2.58, e = 0.67. Properties of clay: Gs = 2.74, e = 0.87. Round off to two decimal places.arrow_forwardKindly solve. Final answers are already givenarrow_forwardQ4 A 0.7m long soil specimen is subject to a steady-state flow, as shown in Figure Q4. The saturated unit weight of the soil is 20 kN/m³. Determine the following: Water 0.3 m 0.8 m А 0.3 m Datum 0.4 m Y Figure Q4 d) Total stress (kPa) at point A, B and C. e) Porewater pressure (kPa) at point A, B and C.arrow_forward
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