Practice of Statistics in the Life Sciences
Practice of Statistics in the Life Sciences
4th Edition
ISBN: 9781319013370
Author: Brigitte Baldi, David S. Moore
Publisher: W. H. Freeman
Question
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Chapter 8, Problem 8.1CRE

a.

To determine

To find: histogram of the given data and also plot the relative frequencies and explain the distribution of weights of newborn babies.

a.

Expert Solution
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Explanation of Solution

Given:

The dataset:

    Weight(Grams)Count
    Less than 5005980
    500 - 99922015
    1000 - 149929846
    1500 - 199963427
    2000 - 2499204295
    2500 - 2999744181
    3000 - 34991566755
    3500 - 39991055004
    4000 - 4499262997
    4500 - 499936706
    5000 - 54994216

Formula used:

  RelativeFrequency = Frequency of classTotal frequency

Calculation:

    Weight(Grams)Relative frequency
    Less than 5000.001
    500 - 9990.006
    1000 - 14990.007
    1500 - 19990.016
    2000 - 24990.051
    2500 - 29990.186
    3000 - 34990.392
    3500 - 39990.264
    4000 - 44990.066
    4500 - 49990.009
    5000 - 54990.001
    Sum1

Graph:

The histogram:

  Practice of Statistics in the Life Sciences, Chapter 8, Problem 8.1CRE , additional homework tip  1

The relative frequency histogram:

  Practice of Statistics in the Life Sciences, Chapter 8, Problem 8.1CRE , additional homework tip  2

Based on the above histogram, it looks that data is approximately normally distributed, though it has a bit larger tail towards the left side, so it can also be considered as the left skewed but since there is not so large difference in tails so it will be better to consider it as approximately normally distributed.

b.

To determine

To find the median class of the data.

b.

Expert Solution
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Explanation of Solution

Formula used:

  Median = (N2)Th term

Calculation:

    Weight(Grams)Count Cumulative frequency.
    Less than 50059805980
    500 - 9992201527995
    1000 - 14992984657841
    1500 - 199963427121268
    2000 - 2499204295325563
    2500 - 29997441811069744
    3000 - 349915667552636499
    3500 - 399910550043691503
    4000 - 44992629973954500
    4500 - 4999367063991206
    5000 - 549942163995422
    Sum3995422

  Median = N2

Median = 39954222=1997711

Now, it required to see that in under which CF value does it falls.

The value 1997711 is less than 2636499, so the median value falls in the class 3000 − 3499.

c.

To determine

To construct the pie chart or bar chart to show the proportion of given categories.

c.

Expert Solution
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Explanation of Solution

Given:

The categories:

Very low birth weight: Less than 1500 grams

Low birth weight: Less than 2500 grams

Normal birth weight: More than 2500 grams

Calculation:

Count of each category:

    Category Frequency Proportion
    Very low birth Weight578410.0144768
    Low birth weight2677220.0670072
    Normal birth weight36698590.918516

Graph:

  Practice of Statistics in the Life Sciences, Chapter 8, Problem 8.1CRE , additional homework tip  3

d.

To determine

To explain the outcome of the analysis that is being done so far.

d.

Expert Solution
Check Mark

Explanation of Solution

Based on the graph prepared in the last part, it is clearly visible that about 8% child having risk of low weight at the time of birth, which indicates at huge proportion of total, it is not an unusual events of being a low weight baby at the time of birth. Tough the distribution if approximately normal but still a large proportion is under the risk of low weight.

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