Integrated Science
7th Edition
ISBN: 9780077862602
Author: Tillery, Bill W.
Publisher: Mcgraw-hill,
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Chapter 8, Problem 4PEA
To determine
The mass of an electron.
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Chapter 8 Solutions
Integrated Science
Ch. 8.1 - Prob. 1SCCh. 8.1 - Prob. 2SCCh. 8.1 - Prob. 3SCCh. 8.1 - Prob. 4SCCh. 8.1 - Prob. 5SCCh. 8.1 - Prob. 6SCCh. 8.2 - Prob. 7SCCh. 8.2 - Prob. 8SCCh. 8.2 - Prob. 9SCCh. 8.3 - Prob. 10SC
Ch. 8.3 - Prob. 11SCCh. 8.3 - Prob. 12SCCh. 8.5 - Prob. 13SCCh. 8.5 - Prob. 14SCCh. 8 - Prob. 1CQCh. 8 - Prob. 2CQCh. 8 - Prob. 3CQCh. 8 - Prob. 4CQCh. 8 - Prob. 5CQCh. 8 - Prob. 6CQCh. 8 - Prob. 7CQCh. 8 - Prob. 8CQCh. 8 - Prob. 9CQCh. 8 - Prob. 10CQCh. 8 - Prob. 11CQCh. 8 - Prob. 12CQCh. 8 - Prob. 13CQCh. 8 - Prob. 14CQCh. 8 - Prob. 15CQCh. 8 - Prob. 16CQCh. 8 - Prob. 17CQCh. 8 - Prob. 18CQCh. 8 - Prob. 1PEACh. 8 - Prob. 2PEACh. 8 - Prob. 3PEACh. 8 - Prob. 4PEACh. 8 - Prob. 1PEBCh. 8 - Prob. 2PEBCh. 8 - Prob. 3PEBCh. 8 - If the charge-to-mass ratio of a proton is 9.58 ...
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- A Thomson-type experiment with relativistic electrons. One of the earliest experiments to show that p = mv (rather than p = mv) was that of Neumann. [G. Neumann, Ann. Physik 45:529 (1914)]. The apparatus shown in Figure P4.5 is identical to Thomsons except that the source of high-speed electrons is a radioactive radium source and the magnetic field B is arranged to act on the electron over its entire trajectory from source to detector. The combined electric and magnetic fields act as a velocity selector, only passing electrons with speed v, where v = V/Bd (Equation 4.6), while in the region where there is only a magnetic field the electron moves in a circle of radius r, with r given by p = Bre. This latter region (E = 0, B = constant) acts as a momentum selector because electrons with larger momenta have paths with larger radii. (a) Show that the radius of the circle described by the electron is given by r = (l2 + y2)/2y. (b) Typical values for the Neumann experiment were d = 2.51 104 m, B = 0.0177 T, and l = 0.0247 m. For V = 1060 V, y, the most critical value, was measured to be 0.0024 0.0005 m. Show that these values disagree with the y value calculated from p = mv but agree with the y value calculated from p = mv within experimental error. (Hint: Find v from Equation 4.6, use mv = Bre or mv = Bre to find r, and use r to find y.) Figure P4.5 The Neumann apparatus.arrow_forwardPart 1 Find the speed an alpha particle requires to come within 4 x 10-14 m of a gold nucleus. Coulomb's constant is 8.99 x 109 Nm2/C2, the charge on an electron is 1.6 × 10-19 C, and the mass of the alpha particle is 6.64 x 10-27 kg. Answer in units of m/s. Part 2 Find the energy of the alpha particle. Answer in units of MeV.arrow_forwardAn Erbium-166 nucleus contains 68 protons. The atomic mass of a neutral Erbium-166 atom is 165.930u, where u = 931.5 MeV/c². In this question you may use that the mass of a proton is 938.27 MeV/c², the mass of a neutron is 939.57 MeV/e² and the mass of an electron is 0.511 MeV/c². i. Calculate the nuclear binding energy per nucleon, giving your answer in units of MeV. ii. Electrons with an energy of 0.5 GeV are scattered off the nucleus. Estimate the scattering angle of the first minimum in the resulting diffraction pattern. iii. Briefly comment on whether or not you expect this nucleus to be spherical, and what consequence this has for excited states of the nucleus in the collective model.arrow_forward
- A proton of energy 10 MeV is moving in Pb. How much energy does it lose in a collision with an electron? How many collisions are required to completely stop it? Solution: Energy lost in a single collision with an electron = E = 0.02179 MeV = 21.79 keV Total number of collisions required to completely stop proton = = 459 collisionsarrow_forwardErnest Rutherford is famous for, among other things, shooting alpha particles at unsuspecting gold atoms. Consider an alpha particle endowed with 5.00 MeV of energy. Determine the closest distance this particle can approach the nucleus of a gold atom before deflectingarrow_forwardThe nucleus of a certain atom has a radius of 4.0 × 10^-15 m. An electron orbits the nucleus at a radius of 1.5 × 10^-10 m. Imagine the electron orbit is on the surface of a sphere and that the shape of the nucleus is spherical. Approximately how many nuclei would fit into the sphere on which the electron orbits?arrow_forward
- X-rays are being produced in a device in which electrons are accelerated to 10 MeV. These high energy electrons interact with ice (solid H20) and stop. They generate X-rays during their slowing down. The 10 MeV electron beam has a power of 1 kW. What is the power rating of the generated X-rays? Express your answer in W.arrow_forwardAn electron is 0.5 Å away from a carbon nucleus which contains 6 protons. Find the mutual force of attraction between the nucleus and the electron. 1Å (Angstrom)= 10^-10m, e=1.6x10^-19C.arrow_forwardA charged particle with initial kinetic energy of 80.3 keV ionizes an electron in the K shell of a silver atom. The binding energy for K-shell electrons in silver is 25.5 keV. The charged particle has kinetic energy of 43.7 keV after the interaction. What is the kinetic energy of the secondary electron, after it is ejected from the silver atom?arrow_forward
- An alpha particle (charge +3.20 x 10^-19C, mass 6.64 x10^-27kg) is initially 5.2cm away from a fixed golden nucleus (charge +1.36 x10^-17C, mass 3.29x10^-25kg), and moving toward the nucleus with a speed of 8.1x10^5m/s. How close to the nucleus does te alpha particle get? Note: the nucleus diameter is approximately 10^-14m and the alpha particles's is 10^-15marrow_forwardDetermine the value of r from the followingarrow_forwardDetermine the distance between the electron and proton in an atom if the potential energy U of the electron is 10.1 eV (electronvolt, 1 eV = 1.6 × 10-19 J). Give your answer in Angstrom (1 A = 10-10 m). Answer: Choose... +arrow_forward
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