a. Sum of “n” numbers using “while” loop: Program: #set the values s = 0 i = 0 #get the input from the user n = eval (input ("Enter the n value: ")) #check "i" is greater than or equal to "n" while i <= n: #sum all the numbers s = s + i #increment the value ...

Question

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Answer 1

Expert Solution & Answer

Chapter 8, Problem 3D

Explanation of Solution

a.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

i = 0

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

  ...

Explanation of Solution

b.

Sum first “n” odd numbers using “while” loop:

Program:

#set the values

s = 0

i = 1

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

...

Explanation of Solution

c.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

#check the condition

while True:

  #get the input from the user

  n= eval(input("Enter a value: "))

  #check "n" is equal to 999

  if n == 999:

    #break the statement

    break

�...

Explanation of Solution

d.

Displaying the number of times a whole number “n” can be divided by 2 using “while” loop:

Program:

#get the input from the user

n = int(input("Enter number: "))

#set the value

count = 0

#check "n" is greater than 1

while(n>1):

  #divide the "n" by 2

  n = n // 2

  #incremen...

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Students have asked these similar questions

Write a while loop fragment that calculates the following values:a) Sum of the first n counting numbers: 1 + 2 + 3 + ... + nb) Sum of the first n odd numbers: 1 + 3 + 5 + ... + 2n - 1c) Sum of a series of numbers entered by the user until the value 999 isentered. Note: 999 should not be part of the sum.d) The number of times a whole number n can be divided by 2 (usinginteger division) before reaching 1 (i.e., log2n).

Integer userNum is read from input. Write a while loop that sums all integers read from input until the integer 1 is read. Integer 1 should not be included in the sum. Ex: If the input is 33 -4 -10 -35 1, then the output is: -16 1 #include 2 using namespace std; 3 4 int main() { 5 6 7 8 9 10 11 12 13 14 15 16 17 int userNum; int result; result = 0; cin >> userNum; while(userNum>0) { } result+=userNum; cin>>userNum; cout << result << endl;

Part B: For Loop Program - using Java Write a program to compute the sum of the first N Fibonacci numbers, where N is an integer that is input by the user. Once it computes the sum, the program will prompt the user for a new value of N. The program will exit if the user enters a non-integer number or string (such as “quit”) instead of an integer. Additionally: For both the above problems, the first four numbers of the Fibonacci sequence are 0, 1, 1, and 2. Part B must use at least one For loop, but may also use while loops.

Answer 2

Expert Solution & Answer

Chapter 8, Problem 3D

Explanation of Solution

a.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

i = 0

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

  ...

Explanation of Solution

b.

Sum first “n” odd numbers using “while” loop:

Program:

#set the values

s = 0

i = 1

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

...

Explanation of Solution

c.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

#check the condition

while True:

  #get the input from the user

  n= eval(input("Enter a value: "))

  #check "n" is equal to 999

  if n == 999:

    #break the statement

    break

�...

Explanation of Solution

d.

Displaying the number of times a whole number “n” can be divided by 2 using “while” loop:

Program:

#get the input from the user

n = int(input("Enter number: "))

#set the value

count = 0

#check "n" is greater than 1

while(n>1):

  #divide the "n" by 2

  n = n // 2

  #incremen...

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Expert Solution & Answer

Chapter 8, Problem 3D

Explanation of Solution

a.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

i = 0

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

  ...

Explanation of Solution

b.

Sum first “n” odd numbers using “while” loop:

Program:

#set the values

s = 0

i = 1

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

...

Explanation of Solution

c.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

#check the condition

while True:

  #get the input from the user

  n= eval(input("Enter a value: "))

  #check "n" is equal to 999

  if n == 999:

    #break the statement

    break

�...

Explanation of Solution

d.

Displaying the number of times a whole number “n” can be divided by 2 using “while” loop:

Program:

#get the input from the user

n = int(input("Enter number: "))

#set the value

count = 0

#check "n" is greater than 1

while(n>1):

  #divide the "n" by 2

  n = n // 2

  #incremen...

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Expert Solution & Answer

Chapter 8, Problem 3D

Explanation of Solution

a.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

i = 0

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

  ...

Explanation of Solution

b.

Sum first “n” odd numbers using “while” loop:

Program:

#set the values

s = 0

i = 1

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

...

Explanation of Solution

c.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

#check the condition

while True:

  #get the input from the user

  n= eval(input("Enter a value: "))

  #check "n" is equal to 999

  if n == 999:

    #break the statement

    break

�...

Explanation of Solution

d.

Displaying the number of times a whole number “n” can be divided by 2 using “while” loop:

Program:

#get the input from the user

n = int(input("Enter number: "))

#set the value

count = 0

#check "n" is greater than 1

while(n>1):

  #divide the "n" by 2

  n = n // 2

  #incremen...

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 8, Problem 3D

Explanation of Solution

a.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

i = 0

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

  ...

Explanation of Solution

b.

Sum first “n” odd numbers using “while” loop:

Program:

#set the values

s = 0

i = 1

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

...

Explanation of Solution

c.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

#check the condition

while True:

  #get the input from the user

  n= eval(input("Enter a value: "))

  #check "n" is equal to 999

  if n == 999:

    #break the statement

    break

�...

Explanation of Solution

d.

Displaying the number of times a whole number “n” can be divided by 2 using “while” loop:

Program:

#get the input from the user

n = int(input("Enter number: "))

#set the value

count = 0

#check "n" is greater than 1

while(n>1):

  #divide the "n" by 2

  n = n // 2

  #incremen...

Answer 8

Chapter 8, Problem 3D

Explanation of Solution

a.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

i = 0

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

  ...

Answer 9

Chapter 8, Problem 3D

Explanation of Solution

a.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

i = 0

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

  ...

Answer 10

Explanation of Solution

b.

Sum first “n” odd numbers using “while” loop:

Program:

#set the values

s = 0

i = 1

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

...

Answer 11

Explanation of Solution

b.

Sum first “n” odd numbers using “while” loop:

Program:

#set the values

s = 0

i = 1

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

...

Answer 12

Explanation of Solution

c.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

#check the condition

while True:

  #get the input from the user

  n= eval(input("Enter a value: "))

  #check "n" is equal to 999

  if n == 999:

    #break the statement

    break

�...

Answer 13

Explanation of Solution

c.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

#check the condition

while True:

  #get the input from the user

  n= eval(input("Enter a value: "))

  #check "n" is equal to 999

  if n == 999:

    #break the statement

    break

�...

Answer 14

Explanation of Solution

d.

Displaying the number of times a whole number “n” can be divided by 2 using “while” loop:

Program:

#get the input from the user

n = int(input("Enter number: "))

#set the value

count = 0

#check "n" is greater than 1

while(n>1):

  #divide the "n" by 2

  n = n // 2

  #incremen...

Answer 15

Explanation of Solution

d.

Displaying the number of times a whole number “n” can be divided by 2 using “while” loop:

Program:

#get the input from the user

n = int(input("Enter number: "))

#set the value

count = 0

#check "n" is greater than 1

while(n>1):

  #divide the "n" by 2

  n = n // 2

  #incremen...

Answer 16

Expert Solution & Answer

Answer 17

Expert Solution & Answer

Answer 18

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Check out a sample textbook solution

See solution

Answer 19

Ch. 8 - Prob. 1TF Ch. 8 - Prob. 2TF Ch. 8 - Prob. 3TF Ch. 8 - Prob. 4TF Ch. 8 - Prob. 5TF Ch. 8 - Prob. 6TF Ch. 8 - Prob. 7TF Ch. 8 - Prob. 8TF Ch. 8 - Prob. 9TF Ch. 8 - Prob. 10TF

a. Sum of “n” numbers using “while” loop: Program: #set the values s = 0 i = 0 #get the input from the user n = eval (input ("Enter the n value: ")) #check "i" is greater than or equal to "n" while i <= n: #sum all the numbers s = s + i #increment the value ...

Solution Summary: The author explains how the "while" loop is used to check "i" is greater than or equal to "n"

Concept explainers

Videos

Explanation of Solution

a.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

i = 0

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

  ...

Explanation of Solution

b.

Sum first “n” odd numbers using “while” loop:

Program:

#set the values

s = 0

i = 1

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

  #sum all the numbers

  s = s + i

  #increment the value

...

Explanation of Solution

c.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

#check the condition

while True:

  #get the input from the user

  n= eval(input("Enter a value: "))

  #check "n" is equal to 999

  if n == 999:

    #break the statement

    break

�...

Explanation of Solution

d.

Displaying the number of times a whole number “n” can be divided by 2 using “while” loop:

Program:

#get the input from the user

n = int(input("Enter number: "))

#set the value

count = 0

#check "n" is greater than 1

while(n>1):

  #divide the "n" by 2

  n = n // 2

  #incremen...

Want to see the full answer?

Chapter 8 Solutions

a. Sum of “n” numbers using “while” loop: Program: #set the values s = 0 i = 0 #get the input from the user n = eval (input ("Enter the n value: ")) #check "i" is greater than or equal to "n" while i &lt;= n: #sum all the numbers s = s + i #increment the value ...

Solution Summary: The author explains how the "while" loop is used to check "i" is greater than or equal to "n"

Concept explainers

Videos

Explanation of Solution

a. Sum of “n” numbers using “while” loop: Program: #set the values s = 0 i = 0 #get the input from the user n = eval (input ("Enter the n value: ")) #check "i" is greater than or equal to "n" while i <= n: #sum all the numbers s = s + i #increment the value ...

Explanation of Solution

b. Sum first “n” odd numbers using “while” loop: Program: #set the values s = 0 i = 1 #get the input from the user n = eval (input ("Enter the n value: ")) #check "i" is greater than or equal to "n" while i <= n: #sum all the numbers s = s + i #increment the value ...

Explanation of Solution

c. Sum of “n” numbers using “while” loop: Program: #set the values s = 0 #check the condition while True: #get the input from the user n= eval(input("Enter a value: ")) #check "n" is equal to 999 if n == 999: #break the statement break �...

Explanation of Solution

d. Displaying the number of times a whole number “n” can be divided by 2 using “while” loop: Program: #get the input from the user n = int(input("Enter number: ")) #set the value count = 0 #check "n" is greater than 1 while(n>1): #divide the "n" by 2 n = n // 2 #incremen...

Want to see the full answer?

Chapter 8 Solutions

a. Sum of “n” numbers using “while” loop: Program: #set the values s = 0 i = 0 #get the input from the user n = eval (input ("Enter the n value: ")) #check "i" is greater than or equal to "n" while i <= n: #sum all the numbers s = s + i #increment the value ...

a.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

i = 0

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

#sum all the numbers

s = s + i

#increment the value

...

b.

Sum first “n” odd numbers using “while” loop:

Program:

#set the values

s = 0

i = 1

#get the input from the user

n = eval (input ("Enter the n value: "))

#check "i" is greater than or equal to "n"

while i <= n:

#sum all the numbers

s = s + i

#increment the value

...

c.

Sum of “n” numbers using “while” loop:

Program:

#set the values

s = 0

#check the condition

while True:

#get the input from the user

n= eval(input("Enter a value: "))

#check "n" is equal to 999

if n == 999:

#break the statement

break

�...

d.

Displaying the number of times a whole number “n” can be divided by 2 using “while” loop:

Program:

#get the input from the user

n = int(input("Enter number: "))

#set the value

count = 0

#check "n" is greater than 1

while(n>1):

#divide the "n" by 2

n = n // 2

#incremen...