a) Explanation Given: The initial pressure of Refrigerant-134a ( P 1 ) is 140 kPa. The initial temperature of Refrigerant-134a ( T 1 ) is − 10 ° C . The work input of the compressor ( W ˙ a , i n ) is 1.3 kW. The final pressure of Refrigerant-134a ( P 2 ) is 700 kPa. The final temperature of Refrigerant-134a ( T 2 ) is 60 ° C . Calculation: Refer the Table – A-13, “superheated refrigerant -134a table”, obtain the following properties of refrigerant at pressure of 140 kPa and temperature of – 10 C. v 1 = 0.14605 m 3 / kg h 1 = 246.37 kJ / kg s 1 = 0.9724 kJ / kg ⋅ K Refer the Table – A-13, “superheated refrigerant -134a table”, obtain the following values for the exit at pressure of 700 kPa and temperature of 60 ° C . The actual enthalpy at exit ( h 2 ) is 298.44 kJ / kg . Refer to Table A-13, “Superheated refrigerant-134a”. Obtain the value of isentropic enthalpy at exit ( h 2 s ) at the isentropic entropy at exit ( s 2 s ) of 0.9724 kJ / kg ⋅ K at pressure of 0.7 MPa by using interpolation method. Show entropy and enthalpy values from the Table A-13 corresponding to the pressure of 0.7 MPa as in below table. Entropy ( s 2 s ) ,in kJ / kg ⋅ K Enthalpy ( h 2 s ) , in kJ / kg 0 b) To determine The volume flow rate at the inlet. c) To determine The maximum volume flow rate at the inlet.

5th Edition

ISBN: 9780078027680

Author: Yunus A. Cengel Dr., Robert H. Turner, John M. Cimbala

Publisher: McGraw-Hill Education

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Chapter 8, Problem 177RQ

To determine

The isentropic efficiency of the compressor.

To determine

The volume flow rate at the inlet.

To determine

The maximum volume flow rate at the inlet.

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Chapter 8, Problem 176RQ

Chapter 8, Problem 178RQ

Chapter 8 Solutions

Fundamentals of Thermal-Fluid Sciences

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