Glencoe Chemistry: Matter and Change, Student Edition
Glencoe Chemistry: Matter and Change, Student Edition
1st Edition
ISBN: 9780076774609
Author: McGraw-Hill Education
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Chapter 8, Problem 136A
Interpretation Introduction

Interpretation:

The number of carbon atoms in acetonitrile is to be determined. The hybridization on each carbon atom is to be determined.

Concept introduction:

The combination of two things that have both the characteristics is termed as a hybrid. The process of mixing of atomic orbitals of different energy to form identical hybrid orbitals of equal energy is termed as hybridization.

Expert Solution & Answer
Check Mark

Answer to Problem 136A

There are two carbon atoms in acetonitrile. The hybridization of the first carbon atom is sp3. The hybridization of the second carbon atom is sp.

Explanation of Solution

The structure of acetonitrile is given as shown below.

Glencoe Chemistry: Matter and Change, Student Edition, Chapter 8, Problem 136A , additional homework tip  1

In the above structure of acetonitrile, there are three hydrogen atoms, two carbon atoms, and one nitrogen atom. Therefore, there are two carbon atoms in acetonitrile.

Glencoe Chemistry: Matter and Change, Student Edition, Chapter 8, Problem 136A , additional homework tip  2

Here, the first carbon atom is surrounded by four electron groups (Three H atoms and one carbon atom). Therefore, the hybridization of the first carbon atom is sp3. The second carbon atom is surrounded by two-electron groups (One C atom and one N atom). Therefore, the hybridization of the second carbon atom is sp.

Glencoe Chemistry: Matter and Change, Student Edition, Chapter 8, Problem 136A , additional homework tip  3

Conclusion

There are two carbon atoms in acetonitrile. The hybridization of the first carbon and second carbon atom is sp3 and sp respectively.

Chapter 8 Solutions

Glencoe Chemistry: Matter and Change, Student Edition

Ch. 8.1 - Prob. 11SSCCh. 8.1 - Prob. 12SSCCh. 8.1 - Prob. 13SSCCh. 8.2 - Prob. 14PPCh. 8.2 - Prob. 15PPCh. 8.2 - Prob. 16PPCh. 8.2 - Prob. 17PPCh. 8.2 - Prob. 18PPCh. 8.2 - Prob. 19PPCh. 8.2 - Prob. 20PPCh. 8.2 - Prob. 21PPCh. 8.2 - Prob. 22PPCh. 8.2 - Prob. 23PPCh. 8.2 - Prob. 24PPCh. 8.2 - Prob. 25PPCh. 8.2 - Prob. 26PPCh. 8.2 - Prob. 27PPCh. 8.2 - Prob. 28PPCh. 8.2 - Prob. 29PPCh. 8.2 - Prob. 30PPCh. 8.2 - Prob. 31SSCCh. 8.2 - Prob. 32SSCCh. 8.2 - Prob. 33SSCCh. 8.2 - Prob. 34SSCCh. 8.2 - Prob. 35SSCCh. 8.2 - Prob. 36SSCCh. 8.3 - Prob. 37PPCh. 8.3 - Prob. 38PPCh. 8.3 - Prob. 39PPCh. 8.3 - Prob. 40PPCh. 8.3 - Prob. 41PPCh. 8.3 - Prob. 42PPCh. 8.3 - Prob. 43PPCh. 8.3 - Prob. 44PPCh. 8.3 - Prob. 45PPCh. 8.3 - Prob. 46PPCh. 8.3 - Prob. 47PPCh. 8.3 - Prob. 48PPCh. 8.3 - Prob. 49PPCh. 8.3 - Prob. 50SSCCh. 8.3 - Prob. 51SSCCh. 8.3 - Prob. 52SSCCh. 8.3 - Prob. 53SSCCh. 8.3 - Prob. 54SSCCh. 8.3 - Prob. 55SSCCh. 8.4 - Prob. 56PPCh. 8.4 - Prob. 57PPCh. 8.4 - Prob. 58PPCh. 8.4 - Prob. 59PPCh. 8.4 - Prob. 60PPCh. 8.4 - Prob. 61SSCCh. 8.4 - Prob. 62SSCCh. 8.4 - Prob. 63SSCCh. 8.4 - Prob. 64SSCCh. 8.4 - Prob. 65SSCCh. 8.4 - Prob. 66SSCCh. 8.4 - Prob. 67SSCCh. 8.5 - Prob. 68SSCCh. 8.5 - Prob. 69SSCCh. 8.5 - Prob. 70SSCCh. 8.5 - Prob. 71SSCCh. 8.5 - Prob. 72SSCCh. 8.5 - Prob. 73SSCCh. 8.5 - Prob. 74SSCCh. 8.5 - Prob. 75SSCCh. 8.5 - Prob. 76SSCCh. 8.5 - Prob. 77SSCCh. 8 - Prob. 78ACh. 8 - Prob. 79ACh. 8 - Prob. 80ACh. 8 - Prob. 81ACh. 8 - Prob. 82ACh. 8 - Prob. 83ACh. 8 - Prob. 84ACh. 8 - Prob. 85ACh. 8 - Prob. 86ACh. 8 - Prob. 87ACh. 8 - Prob. 88ACh. 8 - Prob. 89ACh. 8 - Prob. 90ACh. 8 - Prob. 91ACh. 8 - Prob. 92ACh. 8 - Prob. 93ACh. 8 - Prob. 94ACh. 8 - Prob. 95ACh. 8 - Prob. 96ACh. 8 - Prob. 97ACh. 8 - Prob. 98ACh. 8 - Prob. 99ACh. 8 - Prob. 100ACh. 8 - Prob. 101ACh. 8 - Prob. 102ACh. 8 - Prob. 103ACh. 8 - Prob. 104ACh. 8 - Prob. 105ACh. 8 - Prob. 106ACh. 8 - Prob. 107ACh. 8 - Prob. 108ACh. 8 - Prob. 109ACh. 8 - Prob. 110ACh. 8 - Prob. 111ACh. 8 - Prob. 112ACh. 8 - Prob. 113ACh. 8 - Prob. 114ACh. 8 - Prob. 115ACh. 8 - Prob. 116ACh. 8 - Prob. 117ACh. 8 - Prob. 118ACh. 8 - Prob. 119ACh. 8 - Rank the bonds according to increasing polarity....Ch. 8 - Prob. 121ACh. 8 - Prob. 122ACh. 8 - Use Lewis structures to predict the molecular...Ch. 8 - Prob. 124ACh. 8 - Prob. 125ACh. 8 - Prob. 126ACh. 8 - Prob. 127ACh. 8 - Prob. 128ACh. 8 - Prob. 129ACh. 8 - Prob. 130ACh. 8 - Prob. 131ACh. 8 - Prob. 132ACh. 8 - Prob. 133ACh. 8 - Prob. 134ACh. 8 - Prob. 135ACh. 8 - Prob. 136ACh. 8 - Prob. 137ACh. 8 - Prob. 138ACh. 8 - Prob. 139ACh. 8 - Prob. 140ACh. 8 - Prob. 141ACh. 8 - Prob. 142ACh. 8 - Prob. 143ACh. 8 - Prob. 144ACh. 8 - Prob. 145ACh. 8 - Prob. 1STPCh. 8 - Prob. 2STPCh. 8 - Prob. 3STPCh. 8 - Prob. 4STPCh. 8 - Prob. 5STPCh. 8 - Prob. 6STPCh. 8 - Prob. 7STPCh. 8 - Prob. 8STPCh. 8 - Prob. 9STPCh. 8 - Prob. 10STPCh. 8 - Prob. 11STPCh. 8 - Prob. 12STPCh. 8 - Prob. 13STPCh. 8 - Prob. 14STPCh. 8 - Prob. 15STPCh. 8 - Prob. 16STPCh. 8 - Prob. 17STPCh. 8 - Prob. 18STPCh. 8 - Prob. 19STP
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