Chapter 7.7, Problem 4P

To determine

To Find: The percentage of acid in the mixture.

Answer to Problem 4P

  $55\%$

Explanation of Solution

Given:

  $\begin{array}{l}\text{Quantity of solution 1 : 12}l\\ \text{Amount of acid in solution: 4}5\%\\ \text{Quantity of solution 2: }8l\\ \text{Amount of acid in solution 2: 70}\%\end{array}$

Formula Used:

  $\text{Total amount }\times \text{ \% acid = Amount of acid}$

Calculation:

  $\begin{array}{l}\text{Let the \% of acid be }x\\ \text{Quantity of solution 1 : 12}l\\ \text{Total Amount of solution1 : 12}\times \text{4}5\%=5.4\\ \text{Quantity of solution 2: }8l\\ \text{Total Amount of solution 2: 8}\times \text{70}\%=5.6\\ \text{Mixture: }20x\\ 5.4+5.6=20x\\ \Rightarrow x=\frac{11}{20}\\ \Rightarrow x=0.55\end{array}$

	Total amount X	%acid	= Amount of Acid
1st Solution	12	45	5.4
2nd Solution	8	70	5.6
Mixture	20	55	11

Conclusion:

Thus the amount of acid is $55\%$