EBK PRECALCULUS W/LIMITS
EBK PRECALCULUS W/LIMITS
4th Edition
ISBN: 9781337516853
Author: Larson
Publisher: CENGAGE CO
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Chapter 7.3, Problem 61E
To determine

To find: The values of x,y,and z in the given figure.

Expert Solution & Answer
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Answer to Problem 61E

The values of x,y,and z in the given figure are 60°,67°,and 53° , respectively.

Explanation of Solution

Given information:

The triangle figure is given below:

  EBK PRECALCULUS W/LIMITS, Chapter 7.3, Problem 61E

Concept used:

Angle Sum property of a triangle says that the sum of interior angles of the triangle is 180°.

Exterior angle theorem says that the exterior angle measure at a vertex is equal to the sum of the measures of its opposite interior angles.

Calculations:

From the given figure, we obtain

  x+y+z=180 (Angles sum property of a triangle)x+y=2x+7 (Exterior angle theorem)x+z=2x7 (Exterior angle theorem)

Simplifying,

  x+y+z=180(1)x+y=7 (2)x+z=7 (3)

The steps of solving the system of equations using Row-Echelon Form and Back substitutions are as follows:

Adding the first equation to the second equation to produce a new second equation and adding the first equation to the third equation to produce a new third equation, we get

  {x+y+z=1802y+z=187y+2z=173

Now, adding 2 times the third equation to the second equation to produce a new third equation, we get

  {x+y+z=1802y+z=1873z=159

Solving 3z=159 for z , we obtain z=53 .

Substituting this value in the second equation, we get

  2y+53=1872y=134y=67

Now, substituting the above finding values in the first equation, we get

  x+67+53=180x+120=180x=60

Conclusion:

Therefore, the values of x,y,and z in the given figure are 60°,67°,and 53° , respectively.

Chapter 7 Solutions

EBK PRECALCULUS W/LIMITS

Ch. 7.1 - Prob. 11ECh. 7.1 - Prob. 12ECh. 7.1 - Prob. 13ECh. 7.1 - Prob. 14ECh. 7.1 - Prob. 15ECh. 7.1 - Prob. 16ECh. 7.1 - Prob. 17ECh. 7.1 - Prob. 18ECh. 7.1 - Prob. 19ECh. 7.1 - Prob. 20ECh. 7.1 - Prob. 21ECh. 7.1 - Prob. 22ECh. 7.1 - Prob. 23ECh. 7.1 - Prob. 24ECh. 7.1 - Prob. 25ECh. 7.1 - Prob. 26ECh. 7.1 - Prob. 27ECh. 7.1 - Prob. 28ECh. 7.1 - Prob. 29ECh. 7.1 - Prob. 30ECh. 7.1 - Prob. 31ECh. 7.1 - Prob. 32ECh. 7.1 - Prob. 33ECh. 7.1 - Prob. 34ECh. 7.1 - Prob. 35ECh. 7.1 - Prob. 36ECh. 7.1 - Prob. 37ECh. 7.1 - Prob. 38ECh. 7.1 - Prob. 39ECh. 7.1 - Prob. 40ECh. 7.1 - Prob. 41ECh. 7.1 - Prob. 42ECh. 7.1 - Prob. 43ECh. 7.1 - Prob. 44ECh. 7.1 - Prob. 45ECh. 7.1 - Prob. 46ECh. 7.1 - Prob. 47ECh. 7.1 - Prob. 48ECh. 7.1 - Prob. 49ECh. 7.1 - Prob. 50ECh. 7.1 - Prob. 51ECh. 7.1 - Prob. 52ECh. 7.1 - Prob. 53ECh. 7.1 - Prob. 54ECh. 7.1 - Prob. 55ECh. 7.1 - Prob. 56ECh. 7.1 - Prob. 57ECh. 7.1 - Prob. 58ECh. 7.1 - Prob. 59ECh. 7.1 - Prob. 60ECh. 7.1 - Prob. 61ECh. 7.1 - Prob. 63ECh. 7.1 - Prob. 64ECh. 7.1 - 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