Chapter 7.3, Problem 15PSB

To determine

To calculate : The restrictions on the value on x

Answer to Problem 15PSB

The restrictions on the value on x are ${18}^0>x>0^0$

Explanation of Solution

Given information : A right triangle with an exterior angle equal to $5x^0$ is given

Formula used : The sum of the measures of any two angles in a triangle will be equal to the measure of the exterior of the third angle.

Calculation : Let us assume the second angle B of the right triangle BCD to be of value a . Thus, we get

  ${90}^0+a=5x^0$

Where, we know that the value of a and x will always be positive

  ${90}^0-5x^0>0$ , $x^0>0$

Hence, we get

  ${18}^0>x>0^0$