Principles of Foundation Engineering (MindTap Course List)
Principles of Foundation Engineering (MindTap Course List)
8th Edition
ISBN: 9781305081550
Author: Braja M. Das
Publisher: Cengage Learning
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Chapter 7, Problem 7.9P

Solve Problem 7.8 using Eq. (7.29). Ignore the post-construction settlement.

7.8 Solve Problem 7.4 with Eq. (7.20). Ignore the correction factor for creep. For the unit weight of soil, use γ = 115 lb/ft3.

7.4 Figure 7.3 shows a foundation of 10 ft × 6.25 ft resting on a sand deposit. The net load per unit area at the level of the foundation, qo, is 3000 lb/ft2. For the sand, μs = 0.3, Es = 3200 lb/in.2, Df = 2.5 ft, and H = 32 ft. Assume that the foundation is rigid and determine the elastic settlement the foundation would undergo. Use Eqs. (7.4) and (7.12).

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7.14 Refer to Figure 7.15. For a foundation on a layer of sand, given: B = 5 ft, L = 10 ft, d = 5 ft, B = 26.6°, e = 0.5 ft, and & = 10°. The Pressuremeter testing at the site pro- duced a mean Pressuremeter curve for which the pam) versus AR/R, points are as follow. AR/R. (1) P,(m) (lb/in.?) (2) 0.002 7.2 0.004 24.2 0.008 32.6 0.012 42.4 0.024 68.9 0.05 126.1 0.08 177.65 0.1 210.5 0.2 369.6 What should be the magnitude of Q, for a settlement (center) of 1 in.? Foundation BxL В Figure 7.15 Definition of parameters-B,
6.8 Refer to Figure P6.8. Using the procedure outlined in Section 6.8, determine the average stress increase in the clay layer below the center of the foundation due to the net foundation load of 50 ton. [Use Eq. (6.28).] 4:5 ft 3 ft 50 ton (net load) 10 ft 5 ft x 5 ft Sand y=100 lb/ft! Sand Yat=122 lb/ft³ Groundwater table Ysat ⇒120 lb/ft³ = 0.7 C=0.25 -C, 0,06 Preconsolidation pressure = 2000 lb/ft² Figure P6.8
Problem 1. A column foundation (Figure below) is 3 m × 2 m in plan. The load on the column, including the weight of the foundation is 4500 kN. Determin the average vertical stress increase 4 m beneath the corner of the foundation in the soil layer due to the foundation loading by: a) Boussinesq equations b) 2:1 method Given: Df = 1.5 m, Ø'= 25°, c'= 70 kN/m². 1.5 m 1 m 3m x 2m y = 17 kN/m³ Water level Ysat 19.5 kN/m³
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