(a)
Interpretation:
The molarity of the solution prepared by diluting
Concept introduction:
A solution is prepared by mixing proper amount of solute and solvent. The expression that is used to calculate the amount of dilution of solutions is shown below.
Where,
•
•
•
•
(b)
Interpretation:
The molarity of the solution prepared by diluting
Concept introduction:
A solution is prepared by mixing proper amount of solute and solvent. The expression that is used to calculate the amount of dilution of solutions is shown below.
Where,
•
•
•
•
(c)
Interpretation:
The molarity of the solution prepared by diluting
Concept introduction:
A solution is prepared by mixing proper amount of solute and solvent. The expression that is used to calculate the amount of dilution of solutions is shown below.
Where,
•
•
•
•
(d)
Interpretation:
The molarity of the solution prepared by diluting
Concept introduction:
A solution is prepared by mixing proper amount of solute and solvent. The expression that is used to calculate the amount of dilution of solutions is shown below.
Where,
•
•
•
•
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Check out a sample textbook solutionChapter 7 Solutions
Chemistry for Today: General, Organic, and Biochemistry
- 34. For each of the following solutions, the number of moles of solute is given, followed by the total volume of the solution prepared. Calculate the molarity of each solution. a. 0.754 mol KNO; 225 mL b. 0.0105 in of CaCl; 10.2 mL c. 3.15 mol NaCl; 5.00 L d. 0.499 mol NaBr; 100. mLarrow_forward3.65 Determine the final molarity for the following dilutions. (a) 24.5 mL of 3.0 M solution diluted to 100.0 mL (b) 15.3 mL of 4.22 M solution diluted to 1.00 L (c) 1.45 mL of 0.034 M solution diluted to 10.0 mL (d) 2.35 L of 12.5 M solution diluted to 100.0 Larrow_forwardCalcium carbonate, CaCO3, can be obtained in a very pure state. Standard solutions of calcium ion are usually prepared by dissolving calcium carbonate in acid. What mass of CaCO3 should be taken to prepare 500. mL of 0.0200 M calcium ion solution?arrow_forward
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