Chapter 7, Problem 7.45P

Interpretation Introduction

(a)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Answer to Problem 7.45P

Given the structure name is isopropyl bromide

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

The bromide is in the middle carbon make it into a isopropyl.

Conclusion

Thus given the structure name is isopropyl bromide

Interpretation Introduction

(b)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Answer to Problem 7.45P

Given the structure name is 3-bromo-4-ethylheptane

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Starting from first carbon the bromide is in the third carbon and ethyl is in fourth carbon, and there are total of seven carbon so 3-bromo-4-ethylheptane.

Conclusion

Thus given the structure name is 3-bromo-4-ethylheptane

Interpretation Introduction

(c)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Answer to Problem 7.45P

Given the structure name is 1, 1-dichloro-2-methylcyclohexane

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Starting from first carbon the two chlorine is in the first carbon and methyl is in second carbon, and there are total of six carbon and ring so 1, 1-dichloro-2-methylcyclohexane.

Conclusion

Thus Given the structure name is 1, 1-dichloro-2-methylcyclohexane

Interpretation Introduction

(d)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Answer to Problem 7.45P

Given the structure name is trans-1-chloro-3-iodocyclobutane

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Starting from first carbon the chlorine is in the first carbon and methyl is in third carbon, and there are total of four carbon and ring so trans-1-chloro-3-iodocyclobutane.

Conclusion

Thus Given the structure name is trans-1-chloro-3-iodocyclobutane

Interpretation Introduction

(e)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Answer to Problem 7.45P

Given the structure name is 1-bromo-4-ethyl-3-fluorooctane

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Starting from first carbon the bromide is in the first carbon and methyl is in fourth carbon, and there are total of eight carbon so 1-bromo-4-ethyl-3-fluorooctane.

Conclusion

Thus Given the structure name is 1-bromo-4-ethyl-3-fluorooctane

Interpretation Introduction

(f)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Answer to Problem 7.45P

Given the structure name is (3S)-3-iodo-2-methylnonane

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Starting from first carbon the iodo is in the third carbon and methyl is in second carbon, and there are total of nine carbon so (3S)-3-iodo-2-methylnonane.

Conclusion

Thus Given the structure name is (3S)-3-iodo-2-methylnonane

Interpretation Introduction

(g)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Answer to Problem 7.45P

Given the structure name is (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Starting from first carbon the chloro and bromo is in the first carbon and there are total of six carbon so (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane.

Conclusion

Thus Given the structure name is (1 R, 2R)-trans-1-bromo-2-chlorocyclohexane

Interpretation Introduction

(h)

Interpretation:

To draw the given structure corresponding to each name.

Concept introduction:

Alkyl halides are organic molecules that contains a halogen atom X bonded to sp³ hybridized carbon atom. Alkyl halides are classified as primary (1°), secondary (2°), and tertiary (3°) depending on the number of carbons bonded to the carbon with the halogen. An alkyl halide is named as an alkane with a halogen substituent-that is, as a halo alkane. To name a halogen substituent, change the -ine ending of the name of the halogen to the suffix -o (chlorine-chloro).

Answer to Problem 7.45P

Given the structure name is (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane

Explanation of Solution

To write the corresponding structure. To work backward from a name to the structure.

First find the parent name and draw it according to the number of carbons. Use the suffix to identify the functional group.

Then arrange the number of carbon in the chain. Finally add the substituent to the appropriate carbon.

Starting from first carbon the chloro is in the fourth and fifth carbon and there are total of ten carbons so (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane.

Conclusion

Thus Given the structure name is (5R)-4, 4, 5-trichloro-3, 3-dimethyldecane