Foundations of Astronomy, Enhanced
13th Edition
ISBN: 9781305980686
Author: Michael A. Seeds; Dana Backman
Publisher: Cengage Learning US
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Chapter 7, Problem 4RQ
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The nature of Deuterium and the reason.
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It may be argued on theoretical grounds that the radius of the hydrogen atom should depend only on the fundamental constants h, e, the electrostatic force constant k = 1/4πℰ0, and m (the electron’s mass). Use dimensional analysis to show that the combination of these factors that yields a result with dimensions of length is h2kme2.
The nucleus of a certain atom has a radius of 4.0 × 10^-15 m. An electron orbits the nucleus at a radius of 1.5 × 10^-10 m. Imagine the electron orbit is on the surface of a sphere and that the shape of the nucleus is spherical. Approximately how many nuclei would fit into the sphere on which the electron orbits?
Chapter 7 Solutions
Foundations of Astronomy, Enhanced
Ch. 7 - Prob. 1RQCh. 7 - Prob. 2RQCh. 7 - Prob. 3RQCh. 7 - Prob. 4RQCh. 7 - Prob. 5RQCh. 7 - Prob. 6RQCh. 7 - Prob. 7RQCh. 7 - Prob. 8RQCh. 7 - Prob. 9RQCh. 7 - Prob. 10RQ
Ch. 7 - Prob. 11RQCh. 7 - Prob. 12RQCh. 7 - Prob. 13RQCh. 7 - Prob. 14RQCh. 7 - Prob. 15RQCh. 7 - Prob. 16RQCh. 7 - How is heat different from temperature?Ch. 7 - Prob. 18RQCh. 7 - Prob. 19RQCh. 7 - Prob. 20RQCh. 7 - Prob. 21RQCh. 7 - Prob. 22RQCh. 7 - Could an object be orbiting another object and we...Ch. 7 - Prob. 24RQCh. 7 - How Do We Know? How is the macroscopic world you...Ch. 7 - Prob. 1DQCh. 7 - Prob. 2DQCh. 7 - Prob. 3DQCh. 7 - Prob. 4DQCh. 7 - Prob. 5DQCh. 7 - Prob. 1PCh. 7 - A celestial body has a temperature of 50 K. What...Ch. 7 - Prob. 3PCh. 7 - Prob. 4PCh. 7 - Prob. 5PCh. 7 - Prob. 6PCh. 7 - Prob. 7PCh. 7 - Prob. 8PCh. 7 - Prob. 9PCh. 7 - Prob. 10PCh. 7 - Prob. 11PCh. 7 - Prob. 12PCh. 7 - Prob. 1LTLCh. 7 - Prob. 2LTLCh. 7 - Prob. 3LTLCh. 7 - Prob. 4LTLCh. 7 - Prob. 5LTLCh. 7 - Prob. 6LTLCh. 7 - Prob. 7LTL
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- Nuclear Physics - Nuclear Structure Density= Nuclear Structure Z mass Volume radius r=r04¹/3 ro=1.2x10-¹5 m N A = Z+N 4 The radius r of a nucleus is given in the above figure. The volume of a nucleus is V = Proton 56 Fe nucleus has a total of 56 nucleons (protons + neutrons). The average mass of a nucleon is u = 1.66x10^-27 kg I whin ber Neutron A Z If this unknown nucleus has 60 neutrons, how many protons does it have? Enter a number rr³ (a)Calculate the radius of a 56 Fe nucleus. Write the radius in fm, 1 fm = 10-15 m. Keep 2 decimal places. Enter a number x10-¹5m, fm (b) Calculate the Denisity of a 56Fe nucleus.. Write the result in terms of 1017 kg/m³. Keep 2 decimal places. Enter a number x10¹7kg/m³ () (c) An unknown hacieus has twice the volume of 56Fe. What is the mass number A of this nucleus? Enter a number iarrow_forwardGive handwritten answer onlyarrow_forwardIn a hydrogen atom, an electron is electrically bound to a proton. The binding energy is the energy required to pull the electron away from the proton. The binding energy depends on k = the Coulomb constant = 9 x 109 kg m3 s-2 C-2, h = Planck's constant = 6.6 x 10-34 kg m2 s-1, m = the mass of the electron = 9.1 x 10-31 kg, and e = the magnitude of the electron's charge = 1.6 x 10-19 C. There is only one way to combine k, h, m, and e in such a way that it has units of energy. That is, ?=???ℎ?????E=Akahbmced , where A is a dimensionless constant, and a, b, c, and d are various powers. Assuming A = 1, estimate E, in units of 10-19 J.arrow_forward
- Certain stars are thought to collapse at the end of their lives, combining their protons and electrons to form a neutron star. Such a star could be thought of as a giant atomic nucleus. If a star with a mass equal to that of the sun (of mass 1.99 × 10°0 kg) were to collapse into neutrons, what would be the radius of the star? Answer in units of m.arrow_forwardQuestion 12 of 22 Calculate the mass defect of Nitrogen (A = 14, Z = 7). The atomic mass of Nitrogen is 14.00307 u. (Note: The mass of a hydrogen atom is mH = 1.007825 u, and the mass of the neutron is mN = 1.008665 u.) 00 1.21 u 0.53 u 0.25 u 0.11 u zeroarrow_forwardOne isotope contains an equal number of protons and neutrons, another isotope of the same element has twice the number of neutrons as the first isotope does. What is the ratio of the atomic mass of the first isotope to that of the second?arrow_forward
- 2.1. A neutral atom has the following electronic configuration: 1s? 2s² 2p° 3s² 3p³ (a). How many electrons are in the M shell? (b). How many protons are in the atomic nucleus? (c). To which group of the periodic table does this element belong?arrow_forwardThe nucleus of a particular isotope of beryllium contains 4 protons and 5 neutrons. Which of the following isotopes has a nucleus that has a radius that is approximately 3 times that of the beryllium isotope? 243 Pu 3A1 Mg 135 Baarrow_forwardIn another universe, the electron is a spin@3/2 rather than a spin@1/2 particle, but all other physics are the same as in our universe. In this universe what are the atomic numbers of the lightest two inert gases?arrow_forward
- An Erbium-166 nucleus contains 68 protons. The atomic mass of a neutral Erbium-166 atom is 165.930u, where u = 931.5 MeV/c². In this question you may use that the mass of a proton is 938.27 MeV/c², the mass of a neutron is 939.57 MeV/e² and the mass of an electron is 0.511 MeV/c². i. Calculate the nuclear binding energy per nucleon, giving your answer in units of MeV. ii. Electrons with an energy of 0.5 GeV are scattered off the nucleus. Estimate the scattering angle of the first minimum in the resulting diffraction pattern. iii. Briefly comment on whether or not you expect this nucleus to be spherical, and what consequence this has for excited states of the nucleus in the collective model.arrow_forwardThe protons in a nucleus are approximately 2 ✕ 10−15 m apart. Consider the case where the protons are a distance d = 1.85 ✕ 10−15 m apart. Calculate the magnitude of the electric force (in N) between two protons at this distance.arrow_forwardUsing the data shown in the table, calculate the path radius of the Ca+ ion. Ca+ path radius: Charge (x10-19 С kg) Mass Isotope |(x10-25 & TOOLS x10 Ca+ 0.666 +1.602 Ca?+ 0.666 +3.204 Ba+ 2.28 +1.602 Ba2+ 2.28 +3.204 Ra+ 3.75 +1.602 Ra2+ 3.75 +3.204 Ra3+ 3.75 +4.806 Using the same data table, match the particles to their Path A path label. Answer Bank Path B Ca²+ Ra3+ Ca+ Path C Path D Ba+ Ra+ Ba2+ Path E Ra2+ Path F Path Garrow_forward
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