Introductory Chemistry: An Active Learning Approach
Introductory Chemistry: An Active Learning Approach
6th Edition
ISBN: 9781305079250
Author: Mark S. Cracolice, Ed Peters
Publisher: Cengage Learning
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 7, Problem 32E
Interpretation Introduction

(a)

Interpretation:

The number of formula units in 85.5g of beryllium nitrate is to be calculated.

Concept introduction:

A mole is a basic unit that is used in the International system of units (SI). It is abbreviated as mol. It can be defined as 6.022×1023 units of some quantity which can be atoms, molecules or ions. The quantity 6.022×1023 is called the Avogadro’s number.

Expert Solution
Check Mark

Answer to Problem 32E

The number of formula units in 85.5g of beryllium nitrate is 3.87×1023formula units.

Explanation of Solution

The molecular formula for beryllium nitrate is Be(NO3)2.

The molar mass of nitrogen is 14.01gmol1.

The molar mass of oxygen is 16.00gmol1.

The molar mass of beryllium is 9.012gmol1.

The molar mass of Be(NO3)2 is calculated below.

Totalmolarmass=9.012+(2×14.01)+(6×16.00)=133.032gmol1

Therefore, the molar mass of Be(NO3)2 is 133.032gmol1.

Thus one mole of Be(NO3)2 is 133.032g.

The number of moles in 85.5g of Be(NO3)2 is given below.

MolesofBe(NO3)2=1moleofBe(NO3)2133.032gofBe(NO3)2×weightofBe(NO3)2ing=1moleofBe(NO3)2133.032gofBe(NO3)2×85.5gofBe(NO3)2=0.643molesofBe(NO3)2

The number of formula units in Be(NO3)2 is calculated as,

Formula unitsofBe(NO3)2=(6.022×1023formula unitsofBe(NO3)2×molesofBe(NO3)21moleofBe(NO3)2)

Substitute the number of moles of Be(NO3)2 in above equation,

Formula unitsofBe(NO3)2=(6.022×1023formula unitsofBe(NO3)2×0.643molesofBe(NO3)21moleofBe(NO3)2)=3.87×1023formula unitsofBe(NO3)2

Conclusion

The number of formula units in 85.5g of beryllium nitrate is 3.87×1023formula units3.87×1023.

Interpretation Introduction

(b)

Interpretation:

The number of formula units in 9.42g manganese is to be calculated.

Concept introduction:

A mole is a basic unit that is used in the International system of units (SI). It is abbreviated as mol It can be defined as 6.022×1023 units of some quantity which can be atoms, molecules or ions. The quantity 6.022×1023 is called the Avogadro’s number.

Expert Solution
Check Mark

Answer to Problem 32E

The number of formula units in 9.42g manganese is 1.03×1023formula units.

Explanation of Solution

The molar mass of manganese atom is 54.94gmol1.

Thus, one mole of manganese is 54.94g.

The number of moles in 9.42g of manganese is given below.

Molesofmanganese=1moleofmanganese54.94gofmanganese×weightofmanganeseing=1moleofmanganese54.94gofmanganese×9.42gofmanganese=0.171molesofmanganese

The number of formula units in manganese is calculated below.

Formula unitsofmanganese=(6.022×1023formula unitsofmanganese×molesofmanganese1moleofmanganese)

Substitute the number of moles of manganese in the above equation.

Formula unitsofmanganese=(6.022×1023formula unitsofmanganese×0.171molesofmanganese1moleofmanganese)=1.03×1023formula unitsofmanganese

Conclusion

The number of formula units in 9.42g manganese is 1.03×1023formula units.

Interpretation Introduction

(c)

Interpretation:

The number of molecules in 0.0948gC3H7OH is to be calculated.

Concept introduction:

A mole is a basic unit that is used in the International system of units (SI). It is abbreviated as mol. It can be defined as 6.022×1023 units of some quantity which can be atoms, molecules or ions. The quantity 6.022×1023 is called the Avogadro’s number.

Expert Solution
Check Mark

Answer to Problem 32E

The number of molecules in 0.0948gC3H7OH is 9.49×1020molecules.

Explanation of Solution

The molecular formula is C3H7OH.

The molar mass of carbon is 12.01gmol1.

The molar mass of oxygen is 16.00gmol1.

The molar mass of hydrogen is 1.008gmol1.

The molar mass of C3H7OH is calculated below.

Totalmolarmass=3×12.01+(8×1.008)+16.00=60.094gmol1

Therefore, the molar mass of C3H7OH is 60.094.

Thus one mole of C3H7OH is 60.0094.

The number of moles in 0.0948gC3H7OH is given below.

MolesofC3H7OH=1moleofC3H7OH60.094gofC3H7OH×weightofC3H7OHing=1moleofC3H7OH360.094ggofC3H7OH×0.0948gofC3H7OH=0.001577molesofC3H7OH

The number of molecules in C3H7OH is calculated below.

MoleculesofC3H7OH=(6.022×1023moleculesofC3H7OH×molesofC3H7OH1moleofC3H7OH)

Substitute the number of moles of C3H7OH in above equation.

MoleculesofC3H7OH=(6.022×1023moleculesofC3H7OH×0.001577molesofC3H7OH1moleofC3H7OH)=9.49×1020moleculesofC3H7OH

Conclusion

The number of molecules in 0.0948gC3H7OH is 9.49×1020molecules.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
A certain chemical substance has the following percent composition by mass. Element Mass Percent carbon 25.29% hydrogen 3.891% bromine 56.08% nitrogen 14.75%     Determine the empirical formula for the compound.Enter your answer without subscripts. C12H21Cl3 should be entered as C12H21Cl3. Enter elements in the order C, H, followed by the remaining elements alphabetically. Single elements do not need to have a subscript. CH4 should be entered as CH4, not C1H4.Empirical Formula: Answer
Define the term Formula Mass?
Element Molar mass (g/mol) F 19.00 Sr 87.62 Using the information in the table, calculate the number of formula units in a 33.8 g sample of   Element Molar mass (g/mol)F19.00Sr87.62Using the information in the table, calculate the number of formula units in a 33.8 g sample of strontiumfluoride (SrF2).Write your answer in scientific notation using three significant figures.formula units SrF2

Chapter 7 Solutions

Introductory Chemistry: An Active Learning Approach

Ch. 7 - What do quantities representing 1mole of iron...Ch. 7 - Explain what the term mole means. Why is it used...Ch. 7 - Is the mole a number? Explain.Ch. 7 - Give the name and value of the number associated...Ch. 7 - Determine how many atoms, molecules or formula...Ch. 7 - a How many molecules of boron trifluoride are...Ch. 7 - Calculate the number of moles in each of the...Ch. 7 - a How many atoms of hydrogen are present in...Ch. 7 - In what way are the molar mass of the atoms and...Ch. 7 - How does molar mass differ from molecular mass?Ch. 7 - Find the molar mass of all the following...Ch. 7 - Calculate the molar mass of each of the following:...Ch. 7 - Prob. 23ECh. 7 - Questions 23 to 26: Find the number of moles for...Ch. 7 - Questions 23 to 26: Find the number of moles for...Ch. 7 - Questions 23 to 26: Find the number of moles for...Ch. 7 - Questions 27 to 30: Calculate the mass of each...Ch. 7 - Questions 27 to 30: Calculate the mass of each...Ch. 7 - Questions 27 to 30: Calculate the mass of each...Ch. 7 - Questions 27 to 30: Calculate the mass of each...Ch. 7 - Prob. 31ECh. 7 - Prob. 32ECh. 7 - Prob. 33ECh. 7 - Prob. 34ECh. 7 - Questions 35 and 36:Calculate the mass of each of...Ch. 7 - Questions 35 and 36: Calculate the mass of each of...Ch. 7 - 37. On a certain day a financial website quoted...Ch. 7 - How many carbon atoms has a gentleman given his...Ch. 7 - A person who sweetens coffee with two teaspoons of...Ch. 7 - The mass of 1 gallon of gasoline is about 2.7kg....Ch. 7 - Prob. 41ECh. 7 - a How many molecules are in 3.61g F2? b How many...Ch. 7 - Questions 43 and 44: Calculate the percentage...Ch. 7 - Prob. 44ECh. 7 - Lithium fluoride is used as a flux when welding or...Ch. 7 - Ammonium bromide is a raw material in the...Ch. 7 - Potassium sulfate is found in some fertilizers as...Ch. 7 - Magnesium oxide is used in making bricks to line...Ch. 7 - Zinc cyanide cyanide ion, CN, is a compound used...Ch. 7 - An experiment requires that enough C5H12O be used...Ch. 7 - Molybdenum (Z=42) is an element used in making...Ch. 7 - How many grams of nitrogen monoxide must be...Ch. 7 - How many grams of the insecticide calcium chlorate...Ch. 7 - If a sample of carbon dioxide contains 16.4g of...Ch. 7 - Explain why C6H10 must be a molecular formula,...Ch. 7 - From the following list, identify each formula...Ch. 7 - A certain compound is 52.2 carbon, 13.0 hydrogen,...Ch. 7 - A compound is found to contain 15.94 boron and...Ch. 7 - A researcher exposes 11.89g of iron to a stream of...Ch. 7 - A compound is found to contain 39.12 carbon, 8.772...Ch. 7 - A compound is 17.2C, 1.44%H, and 81.4%F. Find its...Ch. 7 - A compound is found to contain 21.96 sulfur and...Ch. 7 - An antifreeze and coolant widely used in...Ch. 7 - A compound is found to contain 31.42 sulfur, 31.35...Ch. 7 - A compound is 73.1 chlorine, 24.8 carbon, and the...Ch. 7 - A compound is found to contain 25.24 sulfur and...Ch. 7 - Prob. 67ECh. 7 - Prob. 68ECh. 7 - Prob. 69ECh. 7 - Prob. 70ECh. 7 - Prob. 71ECh. 7 - The quantitative significance of take a deep...Ch. 7 - Prob. 73ECh. 7 - Prob. 74ECh. 7 - CoaSbOcXH2O is the general formula of a certain...Ch. 7 - Prob. 1CLECh. 7 - Prob. 2CLECh. 7 - Prob. 1PECh. 7 - Prob. 2PECh. 7 - Prob. 3PECh. 7 - Prob. 4PECh. 7 - Prob. 5PECh. 7 - Determine the mass in grams of 3.21024 molecules...Ch. 7 - Prob. 7PECh. 7 - Prob. 8PECh. 7 - In Practice Exercise 7-7, you determined that...Ch. 7 - Prob. 10PECh. 7 - Prob. 11PECh. 7 - Prob. 12PECh. 7 - Prob. 13PECh. 7 - Nicotine is 74.1 carbon, 8.64 hydrogen, and 17.3...Ch. 7 - A compound has a molar mass of 292g/mol. Its...
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Introductory Chemistry: An Active Learning Approa...
Chemistry
ISBN:9781305079250
Author:Mark S. Cracolice, Ed Peters
Publisher:Cengage Learning
Text book image
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Text book image
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
Text book image
Chemistry: Matter and Change
Chemistry
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Glencoe/McGraw-Hill School Pub Co
Text book image
Introductory Chemistry: A Foundation
Chemistry
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
World of Chemistry, 3rd edition
Chemistry
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Brooks / Cole / Cengage Learning
Step by Step Stoichiometry Practice Problems | How to Pass ChemistryMole Conversions Made Easy: How to Convert Between Grams and Moles; Author: Ketzbook;https://www.youtube.com/watch?v=b2raanVWU6c;License: Standard YouTube License, CC-BY